原因:JavaScript 中的对象(包括数组)是通过引用传递的,所以如果数组元素是对象或数组,那么新数组和原数组将共享这些元素的引用。 解决方法:如果需要进行深拷贝,可以使用递归方法或者其他库(如 Lodash 的 _.cloneDeep)来实现。 代码语言:txt 复制 function deepConcat(arrays) { return arrays.reduce((acc, val) =>...
javascript function concatAndRemoveDuplicates(...arrays) { // 使用 concat 方法合并所有数组 const combinedArray = arrays.reduce((acc, arr) => acc.concat(arr), []); // 使用 Set 对象去重 const uniqueArray = Array.from(new Set(combinedArray)); return uniqueArray; } // 测试函数 const ...
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varlanguages1 = ["JavaScript","Python","Java"];varlanguages2 = ["C","C++"];// concatenating two arrays varnew_arr = languages1.concat(languages2); console.log(new_arr);// [ 'JavaScript', 'Python', 'Java', 'C', 'C++' ]// concatenating a value and array varnew_arr1 = languag...
array1.push(...array2) 一行就解决: 性能对比# 以上3 中数组合并方法的性能测评基于第三方库https://github.com/ecofic/article-efficiently-merging-arrays-in-javascript,可以 clone 下来,运行调试: 这里,我们尝试从 3 个维度来进行测试:(分别用1、10、100、1000、100,000、100,000、1,000,000元素数组进行...
If Array1 contains "AAA", "BBB", "CCC" and Array2 contains "000", "111", "222", then the method call Array1.concat(Array2) will return an array with all the elements in a single collection. The original arrays will be untouched. ...
function deepConcat(arrays) { return arrays.reduce((acc, curr) => { return acc.concat(Array.isArray(curr) ? deepConcat(curr) : curr); }, []); } let nestedArray1 = [1, [2, 3]]; let nestedArray2 = [[4], 5]; let deeplyCombinedArray = deepConcat([nestedArray1, nestedArray2...
Implemented in JavaScript 1.2 Syntax concat(arrayname1, arrayname2, ..., arraynameN) Parameter arrayname1, arrayname2, ..., arraynameN : Arrays to be joined to an array. Example -1: In the following web document two arrays arrayname1 and arrayname2 with single element have joined by ...
function concatArrays(arr1, arr2) { for (var i = 0; i < arr2.length; i++) { arr1.push(arr2[i]); } return arr1; } ``` 二、使用apply()方法实现数组合并 在低版本的JavaScript环境中,我们也可以使用apply()方法来实现数组的合并。apply()方法可以将一个数组作为参数传递给另一个数组的方...
)method is used to merge two or more arrays. This method does not change the existing arrays,...