template<class Type> bool operator==( const complex<Type>& _Left, const complex<Type>& _Right ); template<class Type> bool operator==( const complex<Type>& _Left, const Type& _Right ); template<class Type> bool operator==( const Type& _Left, const complex<Type>& _Right ); 參數...
friend Complex operator *(Complex, Complex);private: double real; double imag;};void Complex::print(){ cout << "(" << real << "+" << imag << "i)";}Complex operator +(Complex c1, Complex c2){ Complex c3(0, 0); c3.real = c1.real + c2.real; c3.imag = c1.imag + c2...
const Complex &c2); // 打印复数 void print();};// 成员函数重载运算符 -Complex Complex::operator-(const Complex &c) const{ return Complex(real - c.real, imag
说明参数是引用类型，如果没有&，调用函数的时候要把实参拷贝到堆栈，然后从堆栈中取 但是一般来说class都比较大，拷贝会浪费堆栈，所以加上&避免了拷贝操作 并且，与一般函数不同的是 像这样的引用型参数的 函数，你在函数体内对参数做的改动都会真实作用在实参上 ...
Complex c1(1,2), c2(3,4)cout 相关知识点: 试题来源: 解析你的测试输出有点问题 我改了下 你看能不能看懂#includeusing namespace stdclass ComplexpublicComplex(double r=0 , double i=0)realPart = rimagePart = iComplex operator +(Complex &c)...
Complex number c1 = (3,4) Complex number c2 = (1.73205,1) The modulus of c2 is: 2 The argument of c2 is: 0.523599 radians, which is 30 degrees. operator==Tests for equality between two complex numbers, one or both of which may belong to the subset of the type for the real and ...
定义一个复数类Complex,重载运算符“+”,“-”,“*”,“/”,使之能用于复数的加、减、乘、除.运算符重载作为Complex的类的成员函数,编程序,求两个复数的和
COMPLEX c1(1, 2); // 定义一个值为1 + 2i的复数c1 COMPLEX c2(2); // 定义一个值为2的复数c2 COMPLEX c3(c1); // 用拷贝构造函数创建一个值同c1的新复数 c3.print(); // 打印c3的值 c1 = c1 + c2 + c3; // 将c1加上c2再加上c3赋值给c1 ...
将指定的复数乘以指定的双精度实数。 Multiply(Complex, Complex) 将两个指定的复数相乘。 注解 Multiply运算符允许执行涉及复数的乘法运算。 它启用以下代码: C# Complex c1 = Complex.One; Complex c2 =newComplex(1.4,2.3); Complex c3 = c1 * c2; ...
Complex operator+(const Complex& c1, const Complex& c2) { double sum_real = c1.real + c2.real; double sum_imaginary = c1.imaginary + c2.imaginary; return Complex(sum_real, sum_imaginary); } int main() { Complex c1(2.0, 3.0); Complex c2(4.0, 5.0); Complex sum = c1...