If two integers have different values, the==operator will returnfalse, while the!=operator will returntrue. 2.2. Objects Let’s say we want to compare twoIntegerwrapper types with the same value: Integera=newIn
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importjava.util.Scanner;publicclassA616{publicstaticvoidmain(String[]args){Scanner sc=newScanner(System.in);String a=sc.nextLine();String b=sc.nextLine();int i=0;for(i=0;i<a.length();i++){if(a.charAt(i)!='0'){break;}}a=a.substring(i);int j;for(j=0;jb.length()){System....
int[] lc, int c) { Map<Integer, Integer> flc = new HashMa
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Description You are given two very long integersa, b(leading zeroes are allowed). You should check what numberaorbis greater or determine that they are equal. The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole lin...
You are given two very long integers a, b (leading zeroes are allowed). You should check what number a or b is greater or determine that they are equal. The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole lin...
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string s1="Include", s2="Help"; Like integers (i==j) , (i>j), (i<j) We can also do the same like if(s1==s2) cout << 'They are same\n"; else if(s1>s2) cout<<s1<<" is greater\n"; else cout<<s2<< "s2 is greater\n"; ...
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