例5、If M is the least common multiple of 90, 196, and 300, which of the following is NOT a factor of M? A 600 B 700 C 900 D 2,100 E 4,900 【答案】A 【解析】90=2×3²×5, 196=2²×7², 300=2²×3×5² 所以,90,196,300的最小公倍数M=2²×3²×5²...
题目: If M is the least common multiple of 90, 196, and 300, which of the following is NOT a factor of M ? 选项: A、600 B、700 C、900 D、2,100 E、4,900 答案: A 提问列表 提问 提问: 不大明白题目说的是什么 解答: 点赞0 阅读4865 解答: sysadmin 提问: 没读懂,也不会算...
If M is the least common multiple of 90, 196, and 300, which of the following is NOT a factor of M? 选项: A、600 B、 700 C、900 D、2,100 E、4,900 答案: A 提问列表 提问: 老师这个数学题要怎么解,解析讲的不是很清楚 解答:...
Then, find the factors that are in the set of factors for all numbers. These are the common factors of the numbers. Finally, find the largest number in the set of common factors. This is the greatest common factor. For example, let’s find the greatest common factor of 90 and 165 by...
Largest Common Factor: The largest common factor is another term for the greatest common factor or GCF. This is a number that is a factor of two or more given numbers and is the largest of all the possible factors that they share. Finding the GCF is helpful when we want to simplify fra...
All of the prime factors of 36 and 90 are [5, 3, 3, 2, 2]. The prime factors common to both 36 and 90 are [3, 3, 2] and the prime factors not common to both 36 and 90 are [5, 2]. This is seen in the Venn diagram above. The prime factor unique to 90 on the left ...
HCF or Highest Common Factor can be found by using the Prime Factorisation method and Division Method. Learn to find HCF by shortcut method or formula with examples at BYJU'S.
12 (a) Find the Highest Common Factor (HCF) of 30 and 42(b) Find the Lowest Common Mutiple (LCM) of 30 and 45 相关知识点: 试题来源: 解析 (a) 30=2×3×542=2×3×7HCF=2×3=6(b) 30,60,90,...45,90,135,...90 反馈 收藏 ...
However, it is doubtful whether factor models are always appropriate. Especially when the common factor is considered to be an attitude, it must be stable through time and explain a considerable part of the variances. A procedure is suggested to test the usefulness of a common factor. In an ...
90 = 2 x 3 x 3 x 5 and 48 = 2 x 2 x 2 x 2 x 3 Identify the common factors. We can see from above that the common factors of 90 and 48 are 2 and 3. For each common prime factor find the minimum number of times it occurs in the prime factorisation of the given numbers....