Java实现 1classSolution {2publicintsmallestCommonElement(int[][] mat) {3intm =mat.length;4intn = mat[0].length;5for(inti : mat[0]) {6booleanfound =true;7for(intj = 0; j < m; j++) {8if(!helper(mat[j], i)) {9found =false;10break;11}12}13if(found) {14returni;15}16...
mat[i]已按递增顺序排列。 1classSolution {2func smallestCommonElement(_ mat: [[Int]]) ->Int {3let n:Int =mat.count4varps:[Int] = [Int](repeating:0,count:n)5let m:Int = mat[0].count6outer:7foriin0..<m8{9forjin1..<n10{11while(ps[j] < m && mat[j][ps[j]] < mat[0...
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There are only lowercase characters in the two strings, and there may be repeated characters;The string key must be spelled out by rotating the string ring. Source: LeetCodeLink: https://leetcode-cn.com/problems/freedom-trail The copyright belongs to Lingkou Network. For commercial ...
classSolution(object):defsmallestCommonElement(self, mat):""":type mat: List[List[int]] :rtype: int"""val= [0] * (10**4+1)foriinrange(len(mat)):forjinrange(len(mat[i])): val[mat[i][j]]|= 2**iforiinrange(len(val)):ifval[i] == 2**len(mat) - 1:returnireturn-1...