whereuser_id= 1。 这个语句里如果像上面这种写法就会报如题这个错误:"Column 'user_id' in where clause is ambiguous"。这时只需要给where后面的user_id指定表名就可以了。 写成如下语句: select u.id,u.user_id,u.user_name,a.user_id,a.money from account a left join user u on u.user_id = ...
该字段在关联表中的出现不止一次,不知道应该查哪一张表。只需在where中加上表名即可 select source.*, t1.username as targetUserName, t2.username as sourceName from sys_message source left join sys_user t1 on source.target_user_id = t1.id left join sys_user t2 on source.source_user_id = ...
这个错误的意思:这个字段不明确 当在java开发中遇到了Column ‘XXX’ in where clause is ambiguous问题时,一般都是多表查询的问题,应该多表查询的时候两张表中字段有相同的,在where条件中那个字段没有明确是那张表的字段,这时你需要去xml语句报错字段明确是哪张表的就OK了。 比如:sys_user_role表有userCode ,sy...
这个错误的意思:这个字段不明确 当在java开发中遇到了Column ‘XXX’ in where clause is ambiguous问题时,一般都是多表查询的问题,应该多表查询的时候两张表中字段有相同的,在where条件中那个字段没有明确是那张表的字段,这时你需要去xml语句报错字段明确是哪张表的就OK了。 比如:sys_user_role表有userCode ,sy...
id) WHERE itemtype = 'Ticket' AND items_id = '7412' AND is_deleted = '0' Error: Column 'itemtype' in where clause is ambiguous Backtrace : src/DBmysqlIterator.php:108 src/DBmysql.php:1046 DBmysqlIterator->execute() src/DbUtils.php:450 DBmysql->request() inc/db.function.php:190 ...
Alternative for OR in WHERE clause Alternative for PIVOT Alternative of CURSOR in SQL to improve performance ? alternative query for in clause Alternative to Full Outer Join Alternative to Row_Number Query Alternative way STUFF for XML PATH ('') ? Am getting an error when i run this code Am...
SQLSTATE[23000]: Integrity constraint violation: 1052 Column ‘created_at’ in where clause is ambiguous The SQL being executed was: SELECT COUNT(*) FROMstatus_logLEFT JOINuserONstatus_log.updated_by=user.idWHEREcreated_at=‘1’ this is my code: ...
[23000]: Integrity constraint violation:1052Column'prof_id'in where clause isambiguous(SQL: select *from`question` whereexists(select *from`prof_skills` inner join `question_profskill` on `prof_skills`.`prof_id` = `question_profskill`.`prof_id` where `question_profskill...
Illuminate\Database\QueryException SQLSTATE[23000]: Integrity constraint violation: 1052 Column 'name' in where clause is ambiguous (SQL: select count(*) as aggregate fromusersleft joinbase_typesonusers.base_type=base_types.idwhere (nameLIKE %uk% oruser_nameLIKE %uk%...
DTS_E_CUSTOMPROPERTYISREADONLY 欄位 DTS_E_CYCLEINEXECUTIONTREE 欄位 DTS_E_DANGLINGWITHPATH 欄位 DTS_E_DATACONVERSIONFAILED 欄位 DTS_E_DATAREADERDESTCANNOTCONVERT 欄位 DTS_E_DATAREADERDESTDATATYPENOTSUPPORTED 欄位 DTS_E_DATAREADERDESTINVALIDCODEPAGE 欄位 DTS_E_DATAREADERDESTINVALIDCOLUMNORDINAL ...