error: column reference "id" is ambiguous 文心快码BaiduComate 当你遇到错误 error: column reference "id" is ambiguous 时,这通常意味着在你的SQL查询中,id 列在多个表中存在,而你没有明确指定你想要引用的是哪个表的 id 列。为了解决这个问题,你可以按照以下步骤操作: 确定查询中涉及的表格及其别名: 首先...
以上SQL 语句试图在 name 字段上插入新值,如果发生冲突,则更新 salary 字段。然而,执行上述语句时会出现 “set column reference is ambiguous” 错误。引用模糊解决方法为了解决 “set column reference is ambiguous” 错误,我们需要明确指定要更新的列。我们可以使用 “EXCLUDED” 关键字来指定...
PG::AmbiguousColumn: ERROR: column reference "name" is ambiguousというエラーが出ます. 解決策 上記のエラーはnameカラムが曖昧だというエラーです。 そこでカテゴリモデルのスコープメソッドにテーブル名を付けます。 category.rb classCategory<ApplicationRecordhas_many:category_users,dependent: ...
postgres column reference "id" is ambiguous 在执行函数时会出现该问题 解决办法: 在查询时为表格指定别名,并且查询字段指定表名如:table.field_name 不过说来也奇怪,我就查一个表,怎么会出现模糊的字段呢 -- 销售报表查询条件,汇总方式可能会有多种情况, /* 月环比: 1. 每个客户的环比, 2. 每个销售人员...
ERROR: column reference "z" is ambiguous at character 8 STATEMENT: SELECT z FROM x, y Explanation: This error occurs when the referenced column can't be resolved unambiguously. This may occur when you have two tables that have columns with the same name. ...
postgrescolumnreferenceidisambiguous postgrescolumnreferenceidisambiguous 在执⾏函数时会出现该问题 解决办法:在查询时为表格指定别名,并且查询字段指定表名如:table.field_name 不过说来也奇怪,我就查⼀个表,怎么会出现模糊的字段呢 -- 销售报表查询条件，汇总⽅式可能会有多种情况，/* ⽉环⽐：1. 每个...
Hi, I have some simple questions created on metabase and PostgreSQL, and after the migration for the latest version i'm getting the following error: I found the generated query on postgresql logs as the following: select count(*) as "cou...
I'll look into this tomorrow but since the update to 2.2.0 I've noticed this issue on sentry; ProgrammingError at /app/model/1/ column reference "id" is ambiguous LINE 1: SELECT (CASE WHEN id='1' THEN 0 END) AS "ordering", "... It compla...
Ambiguous Column Name An aggregate may not appear in the set list of an UPDATE statement... An error occurred while executing batch. Error message is: Error creating window handle. SQL SERVER 2008 An error occurred while executing batch. Error message is: There is not enough space on t...
ActiveRecord::StatementInvalid: PG::AmbiguousColumn: ERROR: column reference "name" is ambiguous LINE 1: ...) AND "projects"."archived" = 'f' ORDER BY lower(name) asc ...^ : SELECT "projects"."id" FROM "projects" LEFT OUTER JOIN "routes" ON "routes"."source_id" = "projects"."...