public SocialUserDetailsImpl(User user, List<String> roleNames) { this.user = user; for (String roleName : roleNames) { GrantedAuthority grant = new SimpleGrantedAuthority(roleName); this.list.add(grant); } } @Override public String getUserId() { return this.user.getUserId() + ""; } @...
1packageCollection集合的增删改查Test;23importjava.util.ArrayList;4importjava.util.Collection;56publicclassDemo01 {7publicstaticvoidmain(String[] args) {8//多态,父类型引用指向子类型对象910Collection<String> list =newArrayList<String>();11//增:12//调用子类ArrayList重写的add方法:向集合中添加元素13lis...
我们可以先创建一个目标List对象,然后调用addAll()方法将其他集合中的所有元素添加到目标List中。示例代码如下: List<String>list1=newArrayList<>();list1.add("apple");list1.add("banana");list1.add("orange");List<String>list2=newLinkedList<>();list2.add("grape");list2.add("watermelon");list...
除了使用构造方法,还可以使用List的addAll方法将集合添加到一个已有的List中。以下是一个示例代码: importjava.util.ArrayList;importjava.util.Collection;importjava.util.List;publicclassCollectionToListExample{publicstaticvoidmain(String[]args){Collection<String>collection=newArrayList<>();collection.add("apple"...
Normally, I'd choose List<String> [or, in VB, List(Of String)] over StringCollection whenever possible: see also Best string container. However, as it seems, generics — and hence, List<String>— are apparently not supported in VS 2008's settings designer. Therefore, if I want to use...
public static void main(String[] args) { test2(); } public static void test1(){ Collection<String> list=new ArrayList<String>(); for(int i=0;i<4;i++) list.add(i+""); String[] ss=list.toArray(new String[0]); for(String s:ss){ ...
因此人们可能会争辩说,简单的foreach(string item in stringCollection)和添加到List<string>中就足够了...
2、数组-->集合:调用Arrays类的静态方法asList() List<String> list = Arrays.asList(newString[]{"as","wa"}); List list1 = Arrays.asList(newint[]{12,123}); System.out.println(list1.size());//返回值为1List list2 = Arrays.asList(newInteger[]{12,123}); ...
extendsGrantedAuthority> getAuthorities() {returnlist; }@OverridepublicStringgetPassword(){returnuser.getPassword(); }@OverridepublicbooleanisAccountNonExpired(){returntrue; }@OverridepublicbooleanisAccountNonLocked(){returntrue; }@OverridepublicbooleanisCredentialsNonExpired(){returntrue;...