And the sum S is set to be 11. First of all we mark that for state 0 (sum 0) we have found a solution with a minimum number of 0 coins. We then go to sum 1. First, we mark that we haven't yet found a solution for this one (a value of Infinity would be fine). Then we...
322. Coin ChangeMedium Topics Companies You are given an integer array coins representing coins of different denominations and an integer amount representing a total amount of money. Return the fewest number of coins that you need to make up that amount. If that amount of money cannot be made...
Epic - Coin Change Something cost $10.25 and the customer pays with a $20 bill, the program will print out the most efficient "change-breakdown" which is 1 five, 4 ones, and 3quarters. Find the minimum number of coins required to make change for a given sum (given unlimited cumber of...
publicclassSolution {publicintcoinChange(int[] coins,intamount) {if(amount == 0)return0;intlen = amount+1;int[] result =newint[len]; result[0] = 0; List<Integer> q =newArrayList<Integer>();intminimumCoins = 1;for(Integer c : coins) {if(c <len) { result[c]=minimumCoins; q.a...
意思是从dp[i - coins[0]] , dp[i - coins[1]] 是走到前一步的dp加上当前的coin一气呵成 https://leetcode.com/problems/coin-change-2/discuss/176706/Beginner-Mistake%3A-Why-an-inner-loop-for-coins-doensn't-work-Java-Soln update 10/2/2020 ...