Coin Change II,不仅是Google、Facebook、Microsoft、Yahoo等公司的高频面试题,也是一道非常经典的动态规划(DP)的题目。 本期习题讲解,我们就通过这道题目,帮助大家对动态规划有一个更进一步的理解。 先一起来看看题目: 题目描述 You are given coins of different denominations and a total amount of money. Write...
int change(int amount, vector<int>& coins) { vector<int> dp(amount + 1); dp[0] = 1; for (auto& coin : coins) { for (int i = coin; i <= amount; i++) { dp[i] += dp[i - coin]; } } return dp[amount]; } 分类: LeetCode 标签: 动态规划 好文要顶 关注我 收藏该...
LightOJ 1232 - Coin Change (II) 【完全背包】 题目链接:http://www.lightoj.com/volume_showproblem.php?problem=1232 题意:每个物品价值为val[i] (>=1),每个物品有k种,组成价值为k的方案数。完全背包。 解法:完全背包计数。 代码: #include <stdio.h> #include <ctime> #include...
1classSolution {2publicintchange(intamount,int[] coins) {3if(amount < 0 || coins ==null){4return0;5}67int[] dp =newint[amount + 1];8dp[0] = 1;910for(intcoin : coins){11for(inti = 1; i <= amount; i++){12if(i - coin < 0){13continue;14}1516dp[i] += dp[i -co...
简介:Golang每日一练(leetDay0110) 零钱兑换I\II Coin Change 322. 零钱兑换 Coin Change 给你一个整数数组coins,表示不同面额的硬币;以及一个整数amount,表示总金额。 计算并返回可以凑成总金额所需的最少的硬币个数。如果没有任何一种硬币组合能组成总金额,返回-1。
[LeetCode] 518. Coin Change 2 You are given coins of different denominations and a total amount of money. Write a function to compute the number of combinations that make up that amount. You may assume that you have infinite number of each kind of coin....
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CoinCarp ranks crypto exchanges including spot exchanges (CEX), decentralized exchanges (DEX), and derivatives (Futures & Perpetual) according to trading volume, web traffic, social trends, on-chain balance, etc. You can also find out the on-chain wallet balance change data of Binance, Coinbase...