问Codeigniter -选择id不在的地方(另一个查询结果)EN回想这几年，就遇到的人和事情而言，有一些触动的...
codeigniter 3 get_where sql查询函数 不在where和where中的复杂SQL查询 多个Where或MS Access查询 使用WHERE和& ILIKE查询 结合"WHERE“查询和LINQ SQL - WHERE和OR with Sub查询 SQL SELECT查询,组合匹配行,使用一个列值where equal或串联where not
OR_WHERE_IN是CodeIgniter中的一个查询构建器方法,用于构建一个OR条件,其中一个字段的值必须在给定的值列表中。它的语法如下:$this->db->or_where_in('field', $values);其中,$values是一个数组,其中包含要搜索的值。CodeIgniter中还有其他where条件,如where,or_where,where_in,or_where_in,where_not_in,or...
->where_in('id',[Math Processing Error]ids);−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−ids是一个数组 ->where_not_in('id',$ids);---与上对立 $array = array('name !=' => $name, 'id...
->where() 支持将任何字符串传递给它,它将在查询中使用它。你可以试试这个:$this->db->select('*')->from('certs');$this->db->where('`id` NOT IN (SELECT `id_cer` FROM `revokace`)', NULL, FALSE);在,NULL,FALSE在where()告诉笨不要逃避...
Generates a WHERE field NOT IN ('item', 'item') SQL query joined with OR if appropriate$names = array('Frank', 'Todd', 'James'); $this->db->or_where_not_in('username', $names); // Produces: OR username NOT IN ('Frank', 'Todd', 'James')...
<?php $names = ['Frank', 'Todd', 'James']; $builder->whereIn('username', $names); // Produces: WHERE username IN ('Frank', 'Todd', 'James') You can use subqueries instead of an array of values:<?php // With closure use CodeIgniter\Database\BaseBuilder; $builder->whereIn('...
('张三','男','1971-10-01');12修改记录:updatenamesetbirthday='1971-01-10'whereuname='张三';13删除记录:deletefromnamewhereuname='张三';14删除表:droptable表名;15删除库:dropdatabase库名;16备份数据库:mysqldump-u root-p--opt 数据库名>备份名; //进入到库目录17恢复数据库:mysql-u root-p ...
Always use single quoted strings unless you need variables parsed, and in cases where you do need variables parsed, use braces to prevent greedy token parsing. You may also use double-quoted strings if the string contains single quotes, so you do not have to use escape characters. ...
/*同更新多条一样不可循环去处理删除 如多条数据主键id都可得,循拼接成字符串 */ $string = '';//需先定义 foreach($someData as $key => $value){ $string .= "'" . $value['id']. "'," ; } $string = rtrim($string,','); $sql = "DELETE FROM xx WHERE id in ? "; $this-...