Codeforces 1227F2 (话说这个题好像同时也是 Codeforces 1262F2 ) 翻译 描述 「你的程序又挂了。这次 WA233 。」 这是这道题的难版。这个版本中,1≤n≤2⋅1051≤n≤2⋅105。如果你锁了这道题,你可以叉这道题。但只有你锁了这道题和上一道题,你才能叉上一道题。(译者注:这段话是对当时比赛规则的
#wronganswer, #implementation -17 potter 3 years ago 2 Comments (1) Show archived | Write comment? notwatermango 3 years ago, # | ← Rev. 2 +1 your code always transform 0 to 1 else: coins+=1 t[i] += 1 where in the test case 6 it's faster to just transform 0 to -...
Codeforces 1262F Wrong Answer on test 233(组合数) E1:设dp[i][j],表示在第i个位置的当前新状态超过原状态j分的方案数是dp[i][j],那么对于这种情况直接进行转移即可,如果a[i]==b[i]显然k种选择都可以,不影响j,如果不一样,这个位置填了a[i]那么状态从dp[i-1][j+1]转移过来,如果填了b[i]就...
The answer is correct in other IDE , but here it is wrong answer. This is the link to my submissionhttps://codeforces.com/contest/114/submission/116726703. Can't find out where I am doing wrong.
Your program fails again. This time it gets "Wrong answer on test 233" . This is the harder version of the problem. In this version, 1≤n≤2⋅105. You can hack this problem if you locked it. But you can hack the previous problem only if you locked both problems. ...
5 如果你打好了代码，就可以点击题目右方的“提交文件”，选择想要提交的源代码文件然后设置好语言（C++，Pascal，Python等）（C++一般用“GNU C++11 5.1.0”）点击下面的“submit”6 过一会，你的评测结果就能出来了各种各样的评测结果：绿色加粗的“Accept”：通过此题蓝色的“Wrong answer on test18”：表示...
00:14:01 A Wrong answer on test 37 [final tests]不多说什么...特殊意义:第一场在正式比赛中爆0双开同时掉Rating传送门:http://codeforces.com/contest/338/standings/participant/1484280#p1484280---参赛ID:waltz7I9比赛:Codeforces Round #196 (Div. 2)Rank : 410Rating - 5(余1576)传送门:http:...
Codeforces赛制的题目会有两套数据,一套称为Pretest,另一套称为System Test,当比赛进行时,您的提交将会用Pretest测评,若通过所有Pretest,则会显示\color{green}\text{Pretests passed}Pretests passed ,否则显示错误的Pretest编号和错误类型,例如\color{red}\text{Wrong answer on pretest 3}Wrong answer on pretest...
管理权限【允许cf接入】: 添加权限 写"codeforces" 把这个url复制下来 进入codeforces-gym-mashups 新建比赛 图片.png 设置比赛名字和时间 进入比赛 添加问题: 测试 Wrong answer on test 2 因为标程是这样: Accepted! 一些其他的东西 设置比赛的管理员 设置比赛的属性...
Apparently this code got WA on test 2. Debugging this is a pretty interesting American task, but I will skip this part (as it is unrelated to intuition) and just say that the issue is that in binary search does not adequately cover the case where the neighboring one is directly larger....