You can see them in https://codeforces.com/problemset/status codeforces, inqueue, bug report Compare Revisions History Revisions Rev.Lang.ByWhenΔComment en1 123asdf123 2024-04-12 06:08:44 94 Initial revision (published) Codeforces (c) Copyright 2010-2025 Mike Mirzayanov The only ...
My submission in the morning suddenly gets a wrong answer QAQ. →Reply sahilanand 3 years ago,#| +4 I thought my Internet was slow XD →Reply Saketd3769 3 years ago,#| 0 Now the older submissions are evaluated but the recent submissions are still in the queue ...
2|0A. Submission Bait 很有迷惑性的签,要根据归纳法,从大往小考虑每个数 如果当前数出现了奇数则先手取之则必胜,因为此时后面的数每个都有偶数个,先手可以镜像操作 因此先手必败的情况当且仅当所有数出现次数为偶数 #include<cstdio> #include<iostream> #include<utility> #include<vector> #include<cstring>...
参考了别人的 http://codeforces.com/contest/589/submission/19431126 用的队列,更简便一点 #include<bits/stdc++.h> using namespace std; int n,m; char mapn[15][15]; char dir[10]="URDL"; int visit[15][15]; int dir_r[4]={-1,0,1,0}; //方向要与"URDL"吻合,mapn[0][0]为左上角...
直到队列为空。 代码 代码语言:javascript 代码运行次数:0 AI代码解释 #include<cstdio>#include<algorithm>#include<queue>#defineN100005using namespace std;int n,b;int ex[N],ey[N],d[N],s[N];queue<int>q;intmain(){scanf("%d",&n);for(int i=0;i<n;i++){scanf("%d%d",&d[i],&s...
#include<iostream>#include<string.h>#include<stdlib.h>#include<algorithm>#include<math.h>#include<stdio.h>#include<queue>using namespace std;#defineMAX1000000char b[MAX+5];char n[MAX+5];long long int c;intmain(){while(scanf("%s%s%lld",b,n,&c)!=EOF){long long int num=0;//blon...
insert(i); //n点不需要作为下滑的终点 vis[n] = 1; queue<int> q; q.push(n); while(!q.empty()) { int t = q.front(); q.pop(); for(auto i = --s.upper_bound(t) ; t-*i<=a[t];) { //s是所有尚未作为跳跃终点的位置集合 //--upper_bound(t)是恰好小于等于t的一个数,...
In the fourth example, the only unsuccessful submission breaks your hopes of having the success rate equal to 1. 题目链接: CodeForces - 807C 题意:给你4个整数,x,y,p,q,P/Q的范围是[0,1],让你求最小的提交数量b,其中a个提交成功使 ( x + a ) / ( y + b ) == p...
The problem consists of two subproblems. The subproblems have different constraints on the input. You will get some score for the correct submission of the subproblem. The description of the subproblems follows. In subproblem B1 (3 points), the constraint 1 ≤ n ≤ 8 will hold. ...
leetcode 题目,可从F12控制台Request Payload中mySubmissionDetail关键词抓取; 使用Java 反射实现 UT 的题目:716、2227、2276、2286; 类中提供接口,UT 中需实现该接口:341、489、702、1095、1428、1533; 一些Trick // 数组 使用 Map<Integer, Integer> 统计每个数值出现的频次int[] nums = {4,1,2,1,2}; ...