3.先将String转换为StringBuffer,调用StringBuffer的reverse函数 public static String reverse1(String str) { return new StringBuffer(str).reverse().toString(); }
下面的代码在leetCode上:Accepted private static String reverseWords(String s) { if (s.length() == 0 || s == null) return ""; String[] str = s.split(" "); StringBuilder builder = new StringBuilder(); for (int i = str.length - 1; i >= 0; i--) { if (!str[i].equals("...
welcome to my blog LeetCode Top Interview Questions 344. Reverse String (Java版; Easy) 题目描述 Write a function that reverses a string. The input string is given as an array of characters char[]. Do not allocate extra space for another array, you must do this by modifying the i...
Input string may contain leading or trailing spaces. However, your reversed string should not contain leading or trailing spaces. You need to reduce multiple spaces between two words to a single space in the reversed string. Follow up: For C programmers, try to solve it in-place in O(1) ...
Given an input string,reverse the string word by word.For example,Given s="the sky is blue",return"blue is sky the". 比较基础的一个题,拿到这个题,我的第一想法是利用vector来存每一个子串,然后在输出,这是一个比较简单的思路,此外,还有第二个思路,就是对所有的字符反转,然后在针对每一个子串反转...
public class Program { public static void main(String[] args) { String x = "Trial Letter"; char[] y = x.toCharArray(); int size = y.length; char[] a = new char[size]; int i = 0; while(i != size){ a[i] = y[size - 1 - i]; ++i; } String reverse = x.r...
The string consists of lower English letters only. Length of the given string and k will in the range [1, 10000] 这道题是之前那道题Reverse String的拓展,同样是翻转字符串,但是这里是每隔k隔字符,翻转k个字符,最后如果不够k个了的话,剩几个就翻转几个。比较直接的方法就是先用n/k算出来原字符串...
Write a function that takes a string as input and reverse only the vowels of a string. Example 1: Givens = "hello", return "holle". Example 2: Givens = "leetcode", return "leotcede". Note 第一种解法:将字符串转化为字符数组,用一头一尾两个指针向中间夹逼,遇到两个元音字母就进行位置交换...
void reverseWords(string &s) { s = removeDuplicateSpace(s); int begin = 0; int end = 0; while(end < s.size()){ if(s[end] == ' '){ swapString(s, begin, end - 1); begin = end+1; end = begin; } else{ end++; } } swapString(s, begin, end - 1)...
Reduce them to a single space in the reversed string. 原问题链接:https://leetcode.com/problems/reverse-words-in-a-string/ 问题分析 这个问题的思路其实比较简单,因为它只是要把一个字符串里所有非空格的词语顺序给倒过来。那么我们就有这么一个基本的思路,首先将这个串按照空格给划分成多个非空的字符串。