void reverseWords(string &s) { s = removeDuplicateSpace(s); int begin = 0; int end = 0; while(end < s.size()){ if(s[end] == ' '){ swapString(s, begin, end - 1); begin = end+1; end = begin; } else{ end++; } } swapString(s, begin, end - 1)...
}voidreverseWords1(string&s) {stringrs;for(inti = s.length()-1; i >=0; ) {while(i >=0&& s[i] =='') i--;if(i <0)break;if(!rs.empty()) rs.push_back('');stringt;while(i >=0&& s[i] !='') t.push_back(s[i--]); reverse(t.begin(), t.end()); rs.append(...
public static String reverseWords(String s) { // reverse the whole string and convert to char array char[] str = reverse(s.toCharArray(), 0, s.length()-1); // System.out.println(str.toString()); int start = 0, end = 0; // start and end positions of a current word for (int...
AI代码解释 voidreverseWords(string&s){string ss;int i=s.length()-1;while(i>=0){while(i>=0&&s[i]==' ')//处理多个空格的情况{i--;}if(i<0)break;if(ss.length()!=0)ss.push_back(' ');string temp;for(;i>=0&&s[i]!=' ';i--)temp.push_back(s[i]);reverse(temp.begin()...
Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let's take LeetCode contest" Output: "s'teL ekat edoCteeL tsetnoc" 1 2 Note: In the string, each word is separated...
151. Reverse Words in a String # 题目 # Given an input string, reverse the string word by word. Example 1: Input: "the sky is blue" Output: "blue is sky the" Example 2: Input: " hello world! " Output: "world! hello" Explanation: Your reversed string s
Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater than or equal to k characters, then reverse...
Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater than or equal to k characters, then reverse...
The string consists of lower English letters only. Length of the given string and k will in the range [1, 10000] 这道题是之前那道题Reverse String的拓展,同样是翻转字符串,但是这里是每隔k隔字符,翻转k个字符,最后如果不够k个了的话,剩几个就翻转几个。比较直接的方法就是先用n/k算出来原字符串...
Reduce them to a single space in the reversed string. 原问题链接:https://leetcode.com/problems/reverse-words-in-a-string/ 问题分析 这个问题的思路其实比较简单,因为它只是要把一个字符串里所有非空格的词语顺序给倒过来。那么我们就有这么一个基本的思路,首先将这个串按照空格给划分成多个非空的字符串。