ListNode next){this.val = val; this.next = next;}*}*/publicListNodeaddTwoNumbers(ListNodel1,ListNodel2){ListNodedummy=newListNode(0);// 创建一个虚拟头节点ListNodecurrent=dummy;// 指针指向虚拟头节点intcarry=0;// 进位标志while(l1!=null||l2!=null){intx=l1!=...
classSolution {publicListNode addTwoNumbers(ListNode l1, ListNode l2) { ListNode l3=null;booleanadd =false;while(l1 !=null|| l2 !=null) {//位数相加intplus;if(l1 ==null) { plus=l2.val; }elseif(l2 ==null) { plus=l1.val; }else{ plus= l1.val +l2.val; }if(add) { plus++; ...
LeetCode.2-两个数字相加(Add Two Numbers) 这是悦乐书的第340次更新,第364篇原创01 看题和准备今天介绍的是LeetCode算法题中Medium级别的第1题(顺位题号是2)。给定两个非空链表,表示两个非负整数。 数字以相反的顺序存储,每个节点包含一个数字。将两个数字相加并将其作为链表返回。你可以假设这两个数字...
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not contain any leading zero, exc...
LeetCode-Java-2. Add Two Numbers 题目 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list....
You are given two non-empty linked lists representing two non-negative integers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not contain any leading zero, excep...
* type ListNode struct { * Val int * Next *ListNode * } */ func addTwoNumbers(l1 *ListNode, l2 *ListNode) *ListNode { // 哨兵结点,方便后续处理 head_pre := &ListNode{} // 结果链表的尾结点,方便用尾插法插入 tail := head_pre // 进位值,初始化为 0 carry := 0 // 如果两个链表...
You are given twonon-emptylinked lists representing two non-negative integers. The digits are stored inreverse order, and each of their nodes contains a single digit. Add the two numbers and return the sum as a linked list. You may assume the two numbers do not contain any leading zero,...
3 输入与输出：/*** Definition for singly-linked list.* struct ListNode {* int val;* ListNode *next;* ListNode(int x) : val(x), next(NULL) {}* };*/class Solution {public: ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { }};4 解决思路：从表头开始相加，记录每次相加...
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