Leetcode c语言-Add Two Numbers Title: You are given twonon-emptylinked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers ...
LeetCode 2. 两数相加(Add Two Numbers)(C++) 题目描述: 给出两个 非空 的链表用来表示两个非负的整数。其中,它们各自的位数是按照 逆序 的方式存储的,并且它们的每个节点只能存储 一位 数字。 如果,我们将这两个数相加起来,则会返回一个新的链表来表示它们的和。 您可以假设除了数字 0 之外,这两个数都...
3 输入与输出：/*** Definition for singly-linked list.* struct ListNode {* int val;* ListNode *next;* ListNode(int x) : val(x), next(NULL) {}* };*/class Solution {public: ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { }};4 解决思路：从表头开始相加，记录每次相加...
classSolution(object):defaddTwoNumbers(self,l1,l2):""":type l1: ListNode:type l2: ListNode:rtype: ListNode"""carry=0cur=dummy=ListNode(0)#遍历l1, l2 链表,并依次赋值给cur 节点whilel1orl2:ifl1andl2:ifl1.val+l2.val+carry>=10:cur.next=ListNode((l1.val+l2.val+carry)%10)carry=1els...
* type ListNode struct { * Val int * Next *ListNode * } */ func addTwoNumbers(l1 *ListNode, l2 *ListNode) *ListNode { // 哨兵结点,方便后续处理 head_pre := &ListNode{} // 结果链表的尾结点,方便用尾插法插入 tail := head_pre // 进位值,初始化为 0 carry := 0 // 如果两个链表...
* You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not contain any leading zero,...
【LeetCode】2. Add Two Numbers You are given twonon-emptylinked lists representing two non-negative integers. The digits are stored inreverse orderand each of their nodes contain a single digit. Add the two numbers and return it as a linked list....
代码运行次数:0 运行 AI代码解释 1ListNode*addTwoNumbers(ListNode*l1,ListNode*l2){2int sum=0;3int i=1;4while(l1!=NULL&&l2!=NULL)5{6sum+=i*(l1->val+l2->val);7i*=10;8l1=l1->next;9l2=l2->next;10}11while(l1!=NULL)12{13sum+=i*(l1->val);14i*=10;15l1=l1->next;16}17...
LeetCode: 2. Add Two Numbers /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *addTwoNumbers( ListNode *l1, ListNode *l2 ) ...
digits数字stored in reverse反向存储 each of每一个nodes节点 3 惊人而又蹩脚的中文翻译 本题主要是类似数据在机器中存储的方式,我们平常所见的数据比如342,在链表中是逆向存储的所以就成了2->4->3这样了,同样5 -> 6 -> 4就是465, 如果这样转换后,我们就会发现342+465=807,在十位上相加是超过10向前进一...