本题方法多多,最简单的方式直接按“ ” spilt即可,JAVA实现如下: 1 2 3 4 5 6 7 8 9 10 11 12 publicString reverseWords(String s) { if(s ==null|| s.length() ==0) returns; String[] str = s.split(" "); StringBuilder sb =newStringBuilder(); for(inti = str.length -1; i >=0...
3.先将String转换为StringBuffer,调用StringBuffer的reverse函数 public static String reverse1(String str) { return new StringBuffer(str).reverse().toString(); }
AI代码解释 voidreverseWords(string&s){string ss;int i=s.length()-1;while(i>=0){while(i>=0&&s[i]==' ')//处理多个空格的情况{i--;}if(i<0)break;if(ss.length()!=0)ss.push_back(' ');string temp;for(;i>=0&&s[i]!=' ';i--)temp.push_back(s[i]);reverse(temp.begin()...
转成字符串: a. 双向队列 b. 双指针 不转字符串: a. 模拟字符串的双向队列(使用math库的log函数 获取整数的位数) b. 反转后面一半的整数(使用math库的log函数 获取整数的位数) c. 反转后面一半的整数(不适用log函数) (通过原整数x 与 reverse_x 的大小判断) 复杂度分析 时间复杂度:O(\log n)O(logn...
【Java】【LeetCode】151. Reverse Words in a String 题目: Given an input string, reverse the string word by word. Example 1: Example 2: Example 3: Note: A word is defined as a sequence of non-space characters. Input string may contai...LeetCode 151. Reverse Words in a String ...
LeetCode: 151. Reverse Words in a String 题目描述 Given an input string, reverse the string word by word. Example: Note: 解题思路 获取用空格分割开的单词,然后将他们的倒序插入结果串中。 AC 代码...LeetCode 151. Reverse Words in a String Given an input string, reverse the string word ...
Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let's take LeetCode contest" Output: "s'teL ekat edoCteeL tsetnoc" ...
importjava.util.Scanner; classLog { publicstaticvoidmain(Stringarg[]) { Scannersc=newScanner(System.in); System.out.println("enter a number n :"); doublen=sc.nextDouble(); System.out.println("enter a base number "); doubleb=sc.nextDouble(); ...
public class Program { public static void main(String[] args) { String x = "Trial Letter"; char[] y = x.toCharArray(); int size = y.length; char[] a = new char[size]; int i = 0; while(i != size){ a[i] = y[size - 1 - i]; ++i; } String reverse = x.rep...
public String reverseVowels(String s) { StringBuilder sb = new StringBuilder(); int j = s.length() - 1; for (int i = 0; i < s.length(); i++) { if ("AEIOUaeiou".indexOf(s.charAt(i)) != -1) { while (j >= 0 && "AEIOUaeiou".indexOf(s.charAt(j)) == -1) j--; ...