int a,b; friend bool operator <(node x,node y) { return x.a>y.a; //如果为 >优先级小的先出队列 反之 } }; priority_queue<node> q; int main() { node a[10]; for(int i=0; i<10; i++) { scanf("%d %d",&a[i].a,&a[i].b); q.push(a[i]); node b; b=q.top()...
不过,LeetCode 引入了 datastructures-js/priority-queue 库,可以使用。 库介绍 LeetCode 编辑器语言选择 JavaScript,它旁边有提示图标,点击看到,如需使用优先队列,可使用datastructures-js/priority-queue@5.3.0。 这个库实现了最大堆、最小堆,以及自行指定优先规则回调的优先队列。 安装 https://www.npmjs.com/pac...
};vector<int>topKFrequent(vector<int>& nums,intk){//定义mapunordered_map<int,int>map;for(inti =0; i < nums.size(); ++i){map[nums[i]]++; }//定义优先级队列priority_queue<pair<int,int>,vector<pair<int,int>>, cmp> que;for(unordered_map<int,int>::iterator it =map.begin(); i...
classSolution{public:inthalveArray(vector<int>&nums){double t=0;priority_queue<double>q;for(auto&n:nums){t+=n;q.push(n);}t/=2.0;int ans=0;while(t>0.0){double n=q.top();q.pop();n/=2.0;t-=n;ans++;q.push(n);}returnans;}}; 208 ms 86.7 MB C++...
for (int i = k; i < nums.length; i++) { //滑动窗口移除最前面的元素,移除是判断该元素是否放入队列 myQueue.poll(nums[i - k]); //滑动窗口加入最后面的元素 myQueue.add(nums[i]); //记录对应的最大值 res[num++] = myQueue.peek(); ...
priority_queue<Pair, vector<Pair>, less<Pair>> que; cout << que.top().first << ' ' << que.top().second << '\n'; que.pop(); set<int> s; 集合的使用,会自动排序,不允许键值重复,反正每个键值唯一 s.insert(x) 通过insert添加元素 ...
size(); vector<int> p(size); auto cmp = [&](const int a, const int b){ return nums[a][p[a]]>nums[b][p[b]]; }; priority_queue<int, vector<int>, decltype(cmp)> pq(cmp); int maxValue=INT_MIN; for(int i=0;i<size;i++){ pq.push(i); p[i] = 0; maxValue = ...
When you create a BlockingCollection object, you can specify not only the bounded capacity but also the type of collection to use. For example, you could specify aQueueContainer<T>object for first in, first out (FIFO) behavior, or aStackContainer<T>object for last in, first out (LIFO) be...
Priority Queue was way easy then I thought it would be , on the other hand Hash tables are more complicated then I thought it would be but everything is more easier then Red Black Trees ! Solved 2 questions (1st and 3rd!!) and would have easily solved 2nd one too but due to wrong...
[0]=0;priority_queue<pair<int,int>,vector<pair<int,int>>,cmp>heap;heap.push({0,0});for(int j=1;j<=n;j++){int idx=lower_bound(preSum.begin(),preSum.end(),preSum[j+1]-maxWeight)-preSum.begin();int i=max(1,max(j-maxBoxes+1,idx));while(!heap.empty()){auto t=heap....