public class Solution { public boolean isPalindrome(int x) { int xl; if(x<0) //1.小于0 return false; for(xl = 1;x/(xl*10)>0;xl++) //2. 得到x的长度 ; if(xl==1) //3.x为个位数时直接返回(由于兴许处理个位数时会使分母为0,故单独处理) return true; for(int i=2;(xl/2)>...
publicclassSolution{publicbooleanisPalindrome(intx){intxl;if(x<0)//1.小于0returnfalse;for(xl=1;x/(xl*10)>0;xl++)//2. 得到x的长度;if(xl==1)//3.x为个位数时直接返回(由于兴许处理个位数时会使分母为0,故单独处理)returntrue;for(inti=2;(xl/2)>=i;i++){if(x%(i*10)/((i-1)*...
leetcode palindrome number(easy) /java 题: 把x翻转后,判断是否与x相等。需考虑溢出。但是如果此数翻转后溢出,那么说明其不是回文数。 推理入下,如果翻转后的数溢出且是回文数,那么原数也溢出。矛盾。 publicclassSolution {publicbooleanisPalindrome(intx) {if(x<0)returnfalse;inty=0,z=x;while(x!=0)...
LeetCode Top Interview Questions 9. Palindrome Number (Java版; Easy) 题目描述 Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. Example 1: Input: 121 Output: true Example 2: Input: -121 Output: false Explanation: From left...
classSolution{publicStringlongestPalindrome(Strings){if(s==null||s.length()<1)return"";intstart=0;intend=0;for(inti=0;i<s.length();i++){intlen1=expandAroundCenter(s,i,i);//以一个字符为中心intlen2=expandAroundCenter(s,i,i+1);//以两个字符为中心intlen=Math.max(len1,len2);if(...
1616-split-two-strings-to-make-palindrome Time: N/A (0%), Space: N/A (0%) - LeetHub Mar 29, 2024 1625-group-sold-products-by-the-date Time: 951 ms (36.07%), Space: 0B (100%) - LeetHub Oct 27, 2023 1641-count-sorted-vowel-strings Time: 0 ms (100%), Space: 40.3 MB ...
LongestChunkedPalindromeDecomposition.go Longest Chunked Palindrome Decomposition Apr 12, 2023 LongestCommonPrefix.java 解决LeetCode.14题,找出最短的一个字符串,随后一个一个比较位,避免超出下标; Mar 16, 2017 LongestCommonPrefix2.java Longest Common Prefix 2 May 29, 2019 ...
For the purpose of this problem, we define empty string as valid palindrome. Java Solution There are several different ways to solve this problem. The following is a solution with O(n) time complexity and O(1) space complexity. publicbooleanisPalindrome(Strings){if(s==null){returnfalse;}s...
For example, given “aacecaaa”, return “aaacecaaa”; given “abcd”, return “dcbabcd”. Java Solution 1 publicStringshortestPalindrome(Strings){inti=0;intj=s.length()-1;while(j>=0){if(s.charAt(i)==s.charAt(j)){i++;}j--;}if(i==s.length())returns;Stringsuffix=s.substring(...
For the purpose of this problem, we define empty string as valid palindrome. 重点是.toLowerCase()和Character.isLetterOrDigit()两个函数的使用; 以及指针在标点情况下移动后的continue语句。 Challenge O(n) time without extra memory. ---> 指针嘛。 Solution...