用deque,首先将nestedIngeter每个item加入队列,进队后判断如果是integer直接加权到res,否则对每个item加入进队列。 classSolution:defdepthSum(self, nestedList: List[NestedInteger]) ->int: queue=collections.deque()foriinnestedList: queue.append(i) res=0 level= 1whilequeue: size=len(queue)foriinrange(si...
* // This is the interface that allows for creating nested lists. * // You should not implement it, or speculate about its implementation * class NestedInteger { * public: * // Return true if this NestedInteger holds a single integer, rather than a nested list. * bool isInteger() const...
remove nested blocks for (const x of Object.keys(a)) { - { - console.log(x); - } + console.log(x); }remove unreachable code function hi() { return 5; - console.log('hello'); }split variable declarations -let a, b; +let a; +let b;...
方便后续可以从栈顶开始遍历nestedList.reverse()# 初始化 NestedIteratorself.stack=nestedListself.next_num=None# 找到下一个要返回的数self.advande_next()defnext(self)->int:next_num:Optional[int]=self.next_num# 找到下一个要返回的数self.advande_next()returnnext_numdefhasNext(self)->bool:#...
具体思路:在初始化迭代器的时候就直接把结果遍历出来,递归遍历列表中的数据,是整数就放入List,不是则再递归遍历,代码结构简单。 public class NestedIterator implements Iterator<Integer> { private List<Integer> list; private int index; public NestedIterator(List<NestedInteger> nestedList) { ...
private void pushData(List<NestedInteger> nestedList) { for (int i = nestedList.size() - 1; i >= 0; i--) { stack.push(nestedList.get(i)); } } } /** * Your NestedIterator object will be instantiated and called as such: ...
A wrapping style applies to various code constructs, specified in the left-hand pane (for example, method call arguments, or assignment statements). Do not wrap - When this option is selected, no special wrapping style is applied, the nested alignment and braces settings are ignored. Wrap if...
* // This is the interface that allows for creating nested lists. * // You should not implement it, or speculate about its implementation * public interface NestedInteger { * * // @return true if this NestedInteger holds a single integer, rather than a nested list. ...
Can you solve this real interview question? Flatten Nested List Iterator - You are given a nested list of integers nestedList. Each element is either an integer or a list whose elements may also be integers or other lists. Implement an iterator to flatte
for(inti = nestedList.size() -1; i >=0; i--) { stack.push(nestedList.get(i)); } } } /** * Your NestedIterator object will be instantiated and called as such: * NestedIterator i = new NestedIterator(nestedList); * while (i.hasNext()) v[f()] = i.next(); ...