Can you solve this real interview question? Maximum Product of Three Numbers - Given an integer array nums, find three numbers whose product is maximum and return the maximum product. Example 1: Input: nums = [1,2,3] Output: 6 Example 2: Input: n
解法二: classSolution {public:intmaximumProduct(vector<int>&nums) {intmx1 = INT_MIN, mx2 = INT_MIN, mx3 =INT_MIN;intmn1 = INT_MAX, mn2 =INT_MAX;for(intnum : nums) {if(num >mx1) { mx3= mx2; mx2 = mx1; mx1 =num; }elseif(num >mx2) { mx3= mx2; mx2 =num; }else...
Description Given an integer array, find three numbers whose product is maximum and output the maximum product. Example 1: Input: [1,2,3] Output: 6 Example 2: Input: [1,2,3,4] Output: 24 Note: The len...628. Maximum Product of Three Numbers Given an integer array, find three nu...
Multiplication of any three numbers in the input won't exceed the range of 32-bit signed integer. 排序,然后前后枚举一下就行了 3种情况。 或者不排序,球最大的3个和最小的三个也可以 classSolution {public:intmaximumProduct(vector<int>&nums) { sort(nums.begin(),nums.end());intn =nums.size...
https://leetcode-cn.com/problems/maximum-product-of-three-numbers/ 耗时 解题:2 h 8 min 题解:8 min 题意 给定一个整型数组,在数组中找出由三个数组成的最大乘积,并输出这个乘积。 思路 一个简单的思想,给数组排序,全是正数自然就是最大的三个正数相乘最大;如果有负数,那就需要考虑两个负数相乘再乘...
简介:Given an integer array, find three numbers whose product is maximum and output the maximum product. Given an integer array, find three numbers whose product is maximum and output the maximum product. Example 1: Input: [1,2,3]
leetcode 628. Maximum Product of Three Numbers Given an integer array, find three numbers whose product is maximum and output the maximum product. Example 1: AI检测代码解析 Input: [1,2,3] Output: 6 1. 2. Example 2: AI检测代码解析...
Given an integer array, find three numbers whose product is maximum and output the maximum product. Example 1: Input: [1,2,3] Output: 6 1. 2. Example 2: Input: [1,2,3,4] Output: 24 1. 2. Note: The length of the given array will be in range [3,104] and all elements are...
How to find the maximum of three numbersSwift version: 5.10 Paul Hudson @twostraws June 4th 2020The easiest way to find the largest of three numbers is to use the max() function with as many parameters as you want to check, like this:...
def maximumProduct(self, nums): """ :type nums: List[int] :rtype: int """ negative_nums = [num for num in nums if num < 0] positive_nums = [num for num in nums if num > 0] positive_nums.sort() negative_nums.sort() is_zero = 0 in nums if len(negative_nums) >= 2: ...