代码(Go) const MAX = 0x3f3f3f3f func minCost(houses []int, cost [][]int, m int, n int, target int) int { // dp[i][j][k] 表示前 i 个房子中,共有 j 个街区, // 且第 i 个房子的颜色为 k 时的最小花费 dp := make([][][]int, m) for i := range dp { dp[i] =...
https://leetcode-cn.com/problems/house-robber/solution/yu-ni-yi-qi-xue-suan-fa-python3-shi-xian-knk6/ https://leetcode-cn.com/problems/house-robber-ii/solution/yu-ni-yi-qi-xue-suan-fa-python3-shi-xian-ifpb/ https://leetcode-cn.com/problems/house-robber/solution/da-jia-jie-she-by...
[0] } // dp[i] 表示从 nums[..=i] 中选择的数的最大和 dp := make([]int, n) // nums[..=0] 中只能选择 nums[0] dp[0] = nums[0] // nums[..=1] 中不能两个都选,只能二选一,贪心选择最大的 dp[1] = max(nums[0], nums[1]) for i := 2; i < n; i++ { // 1...
The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the "root." Besides the root, each house has one and only one parent house. After a tour, the smart thief realized that "all houses in this place forms a binary tree". ...
其实就是rob了两次第一题,rob(start, end)表示从start到end能偷到的最大值,注意并不一定包括end,但一定包括start;可见house robber i不用把整个dp数组初始,需要的只有两个变量oneBefore和twoBefore,分别代表end=i-1和end=i-2时的最大值,遍历时更新即可。
950 按递增顺序显示卡牌 - Reveal Cards In Increasing Order C# C++ Java Python Medium 949 给定数字能组成的最大时间 - Largest Time for Given Digits C# C++ Java Python Easy 948 令牌放置 - Bag of Tokens C# C++ Java Python Medium 947 移除最多的同行或同列石头 - Most Stones Removed with Same ...
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