publicbooleanisHappy2(intn){if(n <=0) {returnfalse; }if(n ==1) {returntrue; } Map<Integer, Integer> map2 =newHashMap<Integer, Integer>();intindex =1;intsum =0;while(true) {for(inti=0; i <(n+"").length(); i++) { sum += Math.pow((n+"").charAt(i)-'0',2); }...
replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers. ...
func isHappy(n int) bool { // used 维护已出现的数字集合 used := make(map[int]bool) // 当 n 未出现过时,继续计算下一个数 for !used[n] { // 标记 n 已出现过 used[n] = true // 计算下一个数,即求 n 的每一位的平方和 nxt := 0 // 当 n 不为 0 时,则还可以计算平方和 for...
isHappy(sum(int(i)**2 for i in str(n))) if n > 4 else n == 1 #一行尾递归 快慢指针解题: **Java: ** class Solution { public boolean isHappy(int n) { int slow = n, fast = helper(n); while (slow != fast) {//条件是快慢指针不相遇 slow = helper(slow); fast = ...
with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers....
Starting with any positive integer, replace the number by the sum of the squares of its digits. Repeat the process until the number equals 1 (where it will stay), or itloops endlessly in a cyclewhich does not include 1. Those numbers for which this processends in 1are happy. ...
Search in a Sorted Infinite Array (medium) Minimum Difference Element (medium) Bitonic Array Maximum (easy) 12. Pattern: Top ‘K’ Elements,前K个系列 任何让我们求解最大/最小/最频繁的K个元素的题,都遵循这种模式。 用来记录这种前K类型的最佳数据结构就是堆了(译者注:在Java中,改了个名,叫优先队...
func isHappy(n int) bool { return isOne(n) } func getSum(n int) int { if n/10 == 0 { return n * n } return (n%10)*(n%10) + getSum(n/10) } func isOne(n int) bool { a := getSum(n) if a == 1 { return true } else if a == 4 { return false } else { ...
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