squared repeatedly. If this method produces an infinite cycle of numbers containing 4, the number is known as an unhappy number. We will look at the implementation of finding out whether a number is a happy num
publicbooleanisHappy2(intn){if(n <=0) {returnfalse; }if(n ==1) {returntrue; } Map<Integer, Integer> map2 =newHashMap<Integer, Integer>();intindex =1;intsum =0;while(true) {for(inti=0; i <(n+"").length(); i++) { sum += Math.pow((n+"").charAt(i)-'0',2); }...
replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers. ...
func isHappy(n int) bool { // used 维护已出现的数字集合 used := make(map[int]bool) // 当 n 未出现过时,继续计算下一个数 for !used[n] { // 标记 n 已出现过 used[n] = true // 计算下一个数,即求 n 的每一位的平方和 nxt := 0 // 当 n 不为 0 时,则还可以计算平方和 for...
with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers....
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func isHappy(n int) bool { return isOne(n) } func getSum(n int) int { if n/10 == 0 { return n * n } return (n%10)*(n%10) + getSum(n/10) } func isOne(n int) bool { a := getSum(n) if a == 1 { return true } else if a == 4 { return false } else { ...