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for i in range(n - 1): x1, y1 = points[i] slope = defaultdict(int) # 用于统计以 points[i] 为起点的所有点的斜率 for j in range(i + 1, n): x2, y2 = points[j] dy, dx = y2 - y1, x2 - x1 g = gcd(dy, dx) # 利用公约数,化成最简形式, 3/6 == 2/4 ...
AI代码解释 #include<iostream>using namespace std;intgcd(int x,int y){return(x%y==0?y:gcd(y,x%y));}intmain(){int x,y,ans=0;cin>>x>>y;if(y%x){cout<<0;return0;}y=y/x;for(int i=1;i*i<=y;i++){if(y%i==0&&gcd(i,y/i)==1)ans+=2;}cout<<ans<<endl;}...
30 Seconds of Java - Essential Code Snippets Library for Java Developers Inspired by 30 seconds of code, this is a collection of reusable, tested, and copy-pasteable Java 21 compatible code snippets that you can understand in 30 seconds or less. If you're interested in contributing to this...
2、GCD 代码语言:javascript 代码运行次数:0 运行 AI代码解释 dispatch_async(dispatch_get_global_queue(0,0), ^{ //耗时操作; dispatch_sync(dispatch_get_main_queue(), ^{ //回到主线程; }); }); 3、Tableview Delegate & DataSource 代码语言:javascript 代码运行次数:0 运行 AI代码解释 - (UITable...
HYBRID JAVA PARALLELIZER: A FRAMEWORK FOR PARALLELIZATION OF JAVA CODEIqbal, A.Khan, M. A.Pakistan Journal of Science
Java 大数基本操作 import java.util.Scanner; import java.math.BigInteger; public class Main { public static void main(String[] args) { BigInteger[] a = new BigInteger[10100]; a[0] = BigInteger.valueOf(1); for(int i = 1;i < 10100;i++) { a[i] = a[i-1].multiply(BigInteger.valu...
(python) morris inorder traversal W56 retainAll Qualcomm-Atheros 0 Tree 生成器模式 人工智能 大数据 硬件 云通讯 通讯 dongt Game Theory industrial wireless AP 量化交易 通信 2.4G&5G GCD Overload Exception Handling Game DP 离散化 Vue min yelp Oriented (python) 后端 802.11r 大数据 Euler Path ...
intg = gcd(numerator, denominator); num = numerator / g; den = denominator / g; // only neededfor negative numbers if(den < 0) { den = -den; num = -num; } } //returnthenumerator and denominator of (this) publicint numerator(){ return num; } ...
Java class Solution { public List<String> simplifiedFractions(int n) { List<String> ans = new ArrayList<String>(); for (int denominator = 2; denominator <= n; ++denominator) { for (int numerator = 1; numerator < denominator; ++numerator) { if (gcd(numerator, denominator) == 1) { ...