算法四:优化counting sort,设关键字为m(本题的关键字为3)一般都比数列n长度小很多,如果使用额外空间O(m),那么就可以节省很多空间。如下面程序处理一下就可以做到了。 const static int NUM_OF_COLORS = 3; void sortColors4(int A[], int n) { int countArray[NUM_OF_COLORS+1] = {0}; for (int ...
sort(colors, left, end, colorMid + 1, colorTo); } } 算法二:计数排序(counting sort) - 题目要求不使用额外的数组,一种方法是使用彩虹排序(rainbow sort),但是这样虽然做到了没有使用额外的空间,但是代价是时间复杂度变成了O(N logK),那么是否有方法做到时间和空间的双赢呢? - 我们重新考虑计数排序(cou...
class Solution: def countingSort(self, nums: [int]) -> [int]: # 找到最大值元素nums_max和最小值元素nums_min nums_min, nums_max = min(nums), max(nums) # 定义计数数组counts,大小为nums_max-nums_min+1 size = nums_max - nums_min + 1 counts = [0 for _ in range(size)] # ...
util.Arrays; public class Solution { // 选择排序:每一轮选择最小元素交换到未排定部分的开头 public int[] sortArray(int[] nums) { int len = nums.length; // 循环不变量:[0, i) 有序,且该区间里所有元素就是最终排定的样子 for (int i = 0; i < len - 1; i++) { // 选择区间 [...
算法二:计数排序(counting sort) - 题目要求不使用额外的数组,一种方法是使用彩虹排序(rainbow sort),但是这样虽然做到了没有使用额外的空间,但是代价是时间复杂度变成了O(N logK),那么是否有方法做到时间和空间的双赢呢? - 我们重新考虑计数排序(counting sort),这里我们需要注意到颜色肯定是1-k,那么k一...
Simple Counting sort in C. Code: #include<stdio.h>#include<string.h>voidcountsorting(intarr[],intn,intn1){// creating an integer array of size n for sorted arrayintoutputArray[n];// creating an integer array of size n1, initialized by zerointfreqArray[n1];memset(freqArray,0,sizeof(...
Working of Counting Sort Find out the maximum element (let it be max) from the given array. Given array Initialize an array of length max+1 with all elements 0. This array is used for storing the count of the elements in the array. Count array Store the count of each element at...
class Solution {public: void sortColors(vector<int>& nums) { int r = 0, g = 0, b = 0; for (int n : nums) { if (n == 0) { nums[b++] = 2; nums[g++] = 1; nums[r++] = 0; } else if (n == 1) { nums[b++] = 2; nums[g++] ...
for (int j = 0; j < array.length - 1 - i; j++) if (array[j + 1] < array[j]) { int temp = array[j + 1]; array[j + 1] = array[j]; array[j] = temp; } return array; } 2、选择排序(Selection Sort) ①基本思想:选择排序(Selection-sort)是一种简单直观的排序算法。它的...
I wondered if I could use the previously built code counting solution to count diffs and get a rough idea of how much change had occurred in the commits of an MR branch and then apply labels to MRs to give at rough idea of their degree of change as a sort of proxy for how much rev...