func construct2DArray(original []int, m int, n int) [][]int { // 如果长度不等于目标二维数组的大小,则直接返回空数组 if len(original) != m * n { return nil } // 定义二维数组 ans := make([][]int, m) // 初始化 (i, j) 处的数 for i := range ans { ans[i] = make([...
Returnanm x n2D array constructed according to the above procedure, or an empty 2D array if it is impossible. Example 1: Input:original = [1,2,3,4], m = 2, n = 2Output:[[1,2],[3,4]]Explanation:The constructed 2D array should contain 2 rows and 2 columns. The first group of...
public: vector<vector<int>>construct2DArray(vector<int>& original,intm,intn) { vector<vector<int>>res; inttotal=original.size(); if(total!=(m*n)) returnres; for(inti=0;i<m;i++) { vector<int>sub; for(intj=0;j<n;j++) { sub.push_back(original[i*n+j]); } res.push_back...
Explanation: The constructed 2D array should contain 2 rows and 2 columns. The first group of n=2 elements in original, [1,2], becomes the first row in the constructed 2D array. The second group of n=2 elements in original, [3,4], becomes the second row in the constructed 2D array...
示例1:corr2d # 二维互相关运算 def corr2d(X, K): h, w = K.shape Y = tf.Variable(tf.zeros(shape=(X.shape[0]-h+1, X.shape[1]-w+1))) for i in range(Y.shape[0]): for j in range(Y.shape[1]): # tf.Variable.assign: Assigns a new value to the variable. ...
In the low-density qubit array case, three CNOTs are used to achieve an equivalent CNOT, as shown in Fig. 2d and f. A stabilizer measurement uses twelve CNOTs because four data qubits are involved. Let us focus our attention on the uppermost CNOT in Fig. 2d, for example. Although the...
class Solution { public: vector<vector<int>> construct2DArray(vector<int>& original, int m, int n) { vector<vector<int>> result; if(original.size() == m * n) for(auto it = original.begin(); it != original.end(); it += n) result.push_back({it, it + n}); return result...
接口调用时返回App has not applied for the Wear Engine service错误信息 打开HR传感器后,没有立刻上报数据 HR传感器数据中,有值为0或255的数据 手机和轻量级智能穿戴设备通信,提示错误码206 手机侧应用发送文件给穿戴设备侧应用时,提示错误码1008500011 更多:若以上FAQ仍不能解决,可通过在线提单反馈 应用质...
int[][] array = new int[m][n]; for(int i = 0;i < original.length;i+=n){ System.arraycopy(original,i,array[i/n],0,n); } return array; } } 代码细节 还有一种方法,就是双重循环拷贝。 一个元素一个元素的拷贝 代码如下 class Solution { public int[][] construct2DArray(int[] or...
tmp.add(array[0]); res.add(tmp); for (int i = 1; i < n; i++) { index = -1; tmp = new ArrayList<Integer>(); for (int j = 0; j < i; j++) { if (array[j] < array[i] && list[j]+1 > list[i]) { list[i] = list[j]+1; ...