Another useful function islast, which returns the last element in the vector: ;; last with a vector(last[:rabbit:pocket-watch:marmalade]);; -> :marmalade;; last with a list(last'(:rabbit:pocket-watch:marmalade))
just returnit.” The quote is necessary because lists are special in Clojure. When Clojure evaluates a list, it tries to interpret the first element of this list as a function (or macro) and the remainder of the list as arguments.
foreach ($arr as $element) { if (!$callback($element)) { return FALSE; } } return TRUE; } /** * Returns true if the given predicate is true for at least one element. * credit: array_every and array_some.php * https://gist.github.com/kid-icarus/8661319 */ function some(calla...
(cond (< (count args) 2) (print-usage) (= 2 (count args)) (copy (first args) (second args)) (> (count args) 2) (copy (first args) (second args) (last args))) (-main "project.clj" "/tmp/copy1.clj") ;; nil (-main "copy1.clj" "/tmp/copy2.clj" "/tmp/") ;; ni...
unable to impact other parts of your system. When you use them, you don’t have to ask yourself, “What could I break by calling this function?” They’re also consistent: you’ll never need to figure out why passing a function the same arguments results in different return values, beca...
Here, if we imagine ourselves onoperator2, looking to the left towards the source is called theupstream. Looking to the right towards the subscriber/consumer is called thedownstream. This is often more apparent when each element is written on a separate line: ...
Last Element ;; Write a function which returns the last element in a sequence. ;; Restrictions (please don't use these function(s)): last ;; (= (__ [1 2 3 4 5]) 5) (defn last-elem [[n & more]] (if more (recur more) n)) (clojure.test/testing "Write a function which ...
Render the body one time for each element in the list. Each render will introduce the following variables into the context:forloop.first forloop.last forloop.counter forloop.counter0 forloop.revcounter forloop.revcounter0 forloop.length forloop.parentloop forloop.previous...
It then invokes (f init x0) where x0 is the first element in xs. f returns a new accumulator value acc1, which is then passed to (f acc1 x1) to produce a new accumulator acc2, and so on until every x in xs is folded into the accumulator. That accumulator is the return value...
and the last element is the rightmost element in the rightmost leaf. For now, we require that all leaf nodes are at the same depth1. As an example, take a look at the tree below: It has the integers 0 to 8 in it, where 0 is the first element and 8 the last. The number 9 is...