C++类中报错:class "xxx" does not name a type 原因 引用的类命名空间未包含 引用的类头文件未包含 包含了头文件,或者已经前置声明了,则说明所引用的类名写错。 循环引用头文件 类内修改了类成员 类中报错 xxx does not name a type可能因为类中修改了对象_JasmineFeng的博客-CSDN博客 ...
转载:http://blog.csdn.net/typename/article/details/7173550 declare class does not name a type 出现这个编译错误主要有四个可能原因,现总结如下: 1.引用的类命名空间未包含 2.引用的类头文件未包含 3.包含了头文件,或者已经前置声明了,则说明所引用的类名写错。 4.循环引用头文件 前置声明要素: 1.前置声...
but right from the get-go I have run into a problem, I have already declared 3 classes in separate headers Class.h Subject.h and Student.h I am getting an error that Student and Class does not name a type but both header are rightfully included. also I decided to put the header guar...
error: '[class name]' does not name a type 这个问题困扰了我好几个小时,真的很痛苦,所以记录一下。 我编译平台是Linux,编译命令如下: 代码语言:javascript 复制 g++-g-Wall-std=c++11-I/usr/local/mysql/include-I/usr/local/curl/include-o obj/tc_mysql.o-c tc_mysql.cpp 从命令中可以看出,我是...
In visual studio code works perfect but when i try code on mingw i took a lot of does not name a type error.I have to say i split my code hpp and cpp actually to much hpp and cpp.I included hpps on cpps but still not working.Here is my code. ...
- the file does not exist where you tried to open it. Its either in another folder or may not exist at all. Eg your program deletes it and then writes a new version, but only got to the delete part before crashing last run, that sort of thing. ...
import java.io.*; abstract class animal{ String name; String type; 可能函数是有返回值的,不是空类型的.还是看看代码吧.
(in 2 separate h files) and I've included them both inside one another. In my first h file, however, the dealers.h, I've made a pointer of type cars(which is the other class/h file) and when I try to compile, I get the error that cars does not name a type. Additionally, ...
:number) =>void, targetLocation: DimensionLocation){constexplodeNoBlocksLoc = Vector3Utils.floor(Vector3Utils.add(targetLocation, { x:1, y:2, z:1})); log("Creating an explosion of radius 15 that does not break blocks."); targetLocation.dimension.createExplosion(explodeNoBlocksLoc,15, { ...
public final classInAvailabilityReasonType extendsExpandableStringEnum<InAvailabilityReasonType> Invalidindicates the name provided does not match Azure App Service naming requirements.AlreadyExistsindicates that the name is already in use and is therefore unavailable. ...