2有如下程序: #include <iostream> using namespace std; class Base public: Base(int x=0) cout<<x; ; class Derived: public Base public: Derived(int x=0) cout<<x; private: Base val; ; int main() Derived d(1); return 0; 程序的输出结果是( )。 A.0 B.1 C.01 D.001 3有如下...
A. class Derived :public Derived {…}; B. class Derived inherits Base {…}; C. class Derived :public Base {…}; D. class Derived :private Base {…}; E. class Derived :Base {…}; 相关知识点: 试题来源: 解析 A,B是错的 反馈...
本题中Derived1公用继承Base,所以①编译正确,Derived2保护继承Base,所以②编译不正确。 结果一 题目 有如下程序:class Base{public:int data;};class Derived1:public Base{};class Derived2:protected Base{};int main(){Derived1 d1;Derived2 d2;d1. data=0; //①d2. data=0; //②return 0;}下列...
class Base2 { www.shyiliangmjg.com/pbpa0 www.chailvbaobao.com/tqxc1 zhuohuaqd.cn/qybd1 www.thetruebooks.com/dycw0 bbwsa.cn/eajo0 public: void show() { std::cout << "Base2 show" << std::endl; } }; class Derived : public Base1, public Base2 { public: void display() {...
23.在下面一段类定义中,Derived类公有继承了基类Base。需要填充的函数由注释内容给出了功能。class Base{ private: int mem1,mem2; //基类的数据成员 public: Base(int m1,int m2) { mem1=m1; mem2=m2;} void output(){cout< //...}; class Derived: public Base{ private: int mem3; //派生...
public; Base(int d); n(d){} }; class Derived: public Base{ public: ___ }; 其中横线处应为类Derived的构造函数的定义。 在下列构造函数的定义中.正确的是___。 A.Derived(int i){Base(i); }B.Derived(int i): Base(i); {}C.Derived(int i){n=i; }D.Derived(int i):...
class Derived: public Base { public: ___ }; 其中横线处应为类Derived的构造函数的定义。在下列构造函数的定义中,正确的是___相关知识点: 试题来源: 解析 Derived(int x): Base(x) { } 反馈 收藏
有如下类声明:class base{int x;public:base(int n){ x=n;}};class derived: public base{int y;public:derived(int a,int b);};下列对构造函数 derived 的定义,正确的是()。 A.derived::derived(int a,int b):base(a),y(b){}B.derived::derived(int a,int b):x(a),y(b){}C.derived:...
1. 有如下程序:#includeusing namespace std;class Base{public:void fun1(){cout<<"Base\n";}virtual void fun2(){cout<<"Base\n";}};class Derived:public Base{public:void fun1(){cout<<"Derived\n";}void fun2(){cout<<"Derived\n";}};void f(Base &B. {b.fun1();b.fun2();}&,...
Example 1: C++ Shadowing Base Class Member Function // C++ program to demonstrate shadowing base class member function#include<iostream>usingnamespacestd;classBase{public:voidprint(){cout<<"Base Function"<<endl; } };classDerived:publicBase {public:voidprint(){cout<<"Derived Function"<<endl; ...