FNF vs Sauce (The Shady Cicada Mod) A funny and cute mod ofFriday Night Funkinwhere boyfriend rap-battle against Shady Cicada’s very own mascot, the Balloon Boy, to the original song from the video,Sauce. Mod Credits: Make sure to support mod creators on their social media by subscribing...
Unique DLs 358 Total DLs 461 Total views 8,394 Version 1.0 Download: Manual 1 items Last updated 07 March 20241:11AM Original upload 07 March 20241:11AM Created by Asuka Uploaded by GengarAsuka Virus scan Safe to use Tags for this mod ...
cicada丿偶如果 立即播放 打开App,流畅又高清100+个相关视频 更多1.2万 26 1:31 App 探索INCREDIBOX SPRUNKI的神秘猫琴弹奏艺术 197 -- 1:04 App 《话唠》 233 -- 2:00 App 成绩出来,我的心情be like 7405 15 1:23 App 【计算器演奏】弹奏人气音乐游戏INCREDIBOX SPRUNKI HORROR MOD 22万 380 1:...
曲名:雨从傍晚下到午夜曲师:Cicada 图:ai(我) cicada,台湾的一个乐队(?),其下的纯音是我近来写作业时最爱听的,总是能写出悠远而又带有着深沉孤独,挑这首只是因为我想推但就这首比较符合自己的要求(这首对提琴的运用,旋律中情感的抒发,不同音色引导的旋律的冲突与合奏可谓信手拈来,将不停息的雨中那般绵长...
constintN =505, mod =998244353, inv2 =499122177;intn,a[N]; LL f[10][N][N],g[N][N];voidmerge(intu,intl,intr){if( l == r )returnf[u][l][l] =1,void();intmid = l+r>>1;merge(u+1,l,mid),merge(u+1,mid+1,r);memset(g,0,sizeofg); ...
export function defineBuiltinValue(mod: Mod, name: string, value: Value): void { mod.builtins.set(name, { 12 changes: 6 additions & 6 deletions 12 src/lang/builtins/defineBuiltins.ts Original file line numberDiff line numberDiff line change @@ -1,9 +1,9 @@ import { Mod } from...
This mod replaces the summer ambience so there are no buzzing flies sounds. Only birds and cicadas.
import type { Mod } from "../mod/index.js" import * as Neutrals from "../neutral/index.js" 6 changes: 5 additions & 1 deletion 6 src/lang/equivalent/equivalentByValue.ts Original file line numberDiff line numberDiff line change @@ -1,6 +1,10 @@ import { indent } from "../...
输出一行nn个数,表示原数列上这个位置在执行后的期望位置,注意输出的是期望值在mod998244353mod998244353下的结果。 回到顶部 数据范围与提示 n⩽500,1⩽ai⩽103n⩽500,1⩽ai⩽103 回到顶部 题解 考虑DPDP,设dp[i][j][k]dp[i][j][k]表示在第ii层下原来的jj在现在排名为kk的概率,发现还是不好...
const int N = 505, mod = 998244353, inv2 = 499122177; int n,a[N]; LL f[N][N][N],g[N][N]; void merge(int u,int l,int r) { if( l == r ) return f[u][l][l] = 1, void(); int mid = l+r>>1; merge(u+1,l,mid), merge(u+1,mid+1,r); ...