C Tutorials Count the Number of Vowels, Consonants and so on Check Whether a Character is an Alphabet or not C isalpha() Find the Frequency of Characters in a String Display Characters from A to Z Using Loop Find ASCII Value of a Character C...
RUN 1: Enter string1: silent Enter string2: listen Strings are anagram RUN 2: Enter string1: integral Enter string2: triangel Strings are anagram RUN 3: Enter string1: abcd Enter string2: abbd Strings are not anagram ExplanationIn the above program, we created two functions checkAnagram()...
In themain()function, we created a character variablechinitialized with 0. Then we read the value ofchfrom the user. Here, we used thematchcase to check vowels. If the given character is not matched with any cases. Then it will be treated as a consonant. ...
Java program to display number of Uppercase letters, Lowercase letters, Numerals, Vowels, Spaces and Special characters contained in a string entered by the user. importjava.io.*;classStringInfo{staticString n;staticintl;publicstaticvoidmain(String args[])throwsIOException{BufferedReader br=newBuffere...
string string2 = "ABCDFGK"; bool result = CheckStrings(string1, string2); Console.WriteLine(result ? "Strings match the criteria" : "Strings do not match the criteria"); } static bool CheckStrings(string s1, string s2) { // Define vowels and consonants ...
The elem function is used to check if the character is in the string "aeiouAEIOU", which contains all the vowels.Open Compiler isVowel :: Char -> Bool isVowel c = c `elem` "aeiouAEIOU" main :: IO () main = do let char1 = 'a' char2 = 'b' putStrLn $ char1 : if isVowel...
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In python we have a function called str() which takes any data as the input and returns the string as output. Mutually disjoint means if no two strings are having the same elements in common. There are different ways to check if all strings are mutually disjoint. Let's go through each ...
= 1]11forwordinwords:12length = len(word) - 113ismyword =True14foriinxrange(length):15if(word[i].upper()invowelsandword[i+1].upper()invowels) \16or(word[i].upper()inconandword[i+1].upper()incon) \17or(word[i]instring.digits):18ismyword =False19break20ifismyword:21count ...
a = c.generate() foo.b = c.generate() return foo } } } For everything else, SwiftCheck defines a number of combinators to make working with custom generators as simple as possible: let onlyEven = Int.arbitrary.suchThat { $0 % 2 == 0 } let vowels = Gen.fromElements(of: [ "A...