Given a binary tree, you need to check whether sum of all covered elements is equal to sum of all uncovered elements or not. In a binary tree, a node is called Uncovered if it appears either on left boundary or right boundary. Rest of the nodes are called covered. For example, conside...
classSolution{publicbooleanisBalanced(TreeNode root){if(root ==null)returntrue;if(Math.abs(height(root.left) - height(root.right)) >1) {returnfalse; }returnisBalanced(root.left) && isBalanced(root.right); }privateintheight(TreeNode root){if(root ==null)return0;returnMath.max(height(root...
Given a binary tree, write an efficient algorithm to check if it has a symmetric structure or not, i.e., left and right subtree mirror each other. For example, the following are some binary trees that have a symmetric structure: Practice this problem The tree has a symmetric structure if ...
The idea is to start from the bottom of the tree and return the size of the subtree rooted at the given node to its parent. The size of a subtree rooted at any node is one more than the sum of the left and right subtree size. The algorithm can be implemented as follows in C++, ...
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go install github.com/atc0005/check-cert/cmd/certsum@latest go install github.com/atc0005/check-cert/cmd/lscert@latest go install github.com/atc0005/check-cert/cmd/cpcert@latest GOBIN="${PWD}" go install github.com/atc0005/check-cert/cmd/check_cert@latest sudo mv check_cert /path/to...
(?:^|/)go\.sum$ (?:^|/)package(?:-lock|)\.json$ (?:^|/)Pipfile$ (?:^|/)pyproject.toml (?:^|/)requirements(?:-dev|-doc|-test|)\.txt$ (?:^|/)vendor/ \.a$ \.ai$ \.all-contributorsrc$ \.avi$ \.bmp$ \.bz2$ \.cer$ \.class$ \.code-workspace$ \.coveragerc$...
TreeNode*left; TreeNode*right; TreeNode(intdata) { val=data; left=NULL; right=NULL; } };intsumTree(TreeNode*root) {if(!root)return0;//if current node is leaf node return it's sumif(!root->left&&!root->right)returnroot->val;//left subtree sumintl=sumTree(root->left);//right ...
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