// Function to check if a given string is a palindrome using recursion function isPalindrome(str) { // Base case: if the string has 0 or 1 characters, it's a palindrome if (str.length <= 1) { return true; } // Check if the first and last characters are equal if (str[0] !=...
If the cleaned string and its reversed form are equal, the input string is a palindrome, and the function returns true. Otherwise, it returns false. In the "main()" function, two sample strings (str1 and str2) are defined. The "isPalindrome()" function is called for each string, and...
# Python program to check if a string is # palindrome or not # function to check palindrome string def isPalindrome(string): rev_string = string[::-1] return string == rev_string # Main code x = "Google" if isPalindrome(x): print(x,"is a palindrome string") else: print(x,"is...
) else: print("The string is not a palindrome.") Run Code Output The string is a palindrome. Note: To test the program, change the value of my_str in the program. In this program, we have taken a string stored in my_str. Using the method casefold() we make it suitable for ...
functionpalindromeFn(string){conststringLength=string.length;for(leti=0;i<stringLength/2;i++){if(string[i]!==string[stringLength-1-i]){return'It is not a palindrome.';}}return'It is a palindrome.';}console.log(palindromeFn('aviddiva'));console.log(palindromeFn('Hello')); ...
The program begins by prompting the user to input a string using theinput()function. This allows us to dynamically test any string for palindromic properties. The core logic lies in the following lines: ifstr(word)==str(word)[::-1]:print("Palindrome") ...
Below is an example to find if the string is a palindrome using JavaScript String and Array Methods ? Open Compiler // Function to check for Palindrome function isPalindrome(str) { const lowerCaseStr = str.toLowerCase(); const modifiedStr = lowerCaseStr.replace(/[\W_]/g, ''); const re...
The program takes a string and checks whether a string is a palindrome or not using recursion. Problem Solution 1. Take a string from the user. 2. Pass the string as an argument to a recursive function. 3. In the function, if the length of the string is less than 1, return True. ...
Checking a variable is string using type() function type()function accepts one parameter (others are optional), and returns its type. Syntax type(object) Example # variablesa=100# an integer variableb=10.23# a float variablec='A'# a character variabled='Hello'# a string variablee="Hello...
My logic: There can be only one occurrence of odd number of character in palindrome string. #include<iostream>#include<algorithm>#include<unordered_map>usingstd::cout;usingstd::endl;intmain(intargc,constchar* argv[]){chararr[] ="tact coa"; ...