public class palindrome { public static void main(String[] args) { StringBuffer strBuf1 = new StringBuffer("malayalam"); StringBuffer strBuf2 = new StringBuffer("malayalam"); strBuf2.reverse(); System.out.println(strBuf2); System.out.println((strBuf1.toString()).equals(strBuf2.toString...
#include <iostream> #include <string> using std::cin; using std::cout; using std::endl; using std::equal; using std::remove; using std::string; bool checkPalindrome(string& s) { string tmp = s; transform(tmp.begin(), tmp.end(), tmp.begin(), [](unsigned char c) { return to...
# Palindrome of string str=raw_input("Enter the string\n") ln=len(str) for i in range(ln/2) : if(str[ln-i-1]!=str[i]): break if(i==(ln/2)-1): print "Palindrome" else: print "Not Palindrome" Share Improve this answer Follow edited Apr 15, 2016 at 11:29 answered A...
1)==Trueassertcan_create_k_palindrome_strings("aaabbbccc",2)==Trueassertcan_create_k_palindrome_strings("aaabbbccc",3)==Falseassertcan_create_k_palindrome_strings("aabbccddee",3)==Trueassertcan_create_k_palindrome_strings("aabbccddee",4)==False...
function palindromeFn(string) { const stringLength = string.length; for (let i = 0; i < stringLength / 2; i++) { if (string[i] !== string[stringLength - 1 - i]) { return 'It is not a palindrome.'; } } return 'It is a palindrome.'; } console.log(palindromeFn('aviddiva...
boolisPalindrome(stringstr,intlow,inthigh) { // 基本情況 if(low>=high){ returntrue; } return(str[low]==str[high])&& isPalindrome(str,low+1,high-1); } // 檢查是否存在重複子序列的函數 // 在字符串中 boolhasRepeatedSubsequence(stringstr) ...
string_to_check = input("Enter a string") if string_to_check == string_to_check[::-1]: print("This is a palindrome") else: print("This is not a palindrome" Here, I'm just reversing it, then comparing it with the original ...
Sometimes you want to check if one String contains another String or SubString or not e.g. "HelloWorld" contains "Hello" and "World"SubString. There are many ways to check SubString in String in Java e.g.contains(),indexOf(),ormatches()method ofjava.lang.Stringclass. In the last articl...
comparing it with emptyString literallike"".equals(str),this method is not as fast as the previous two but it is null safe, you don't need to check for null, in case of null it will return false.So, in my opinion, this is the right way to check if the String is empty or not...
string 1Answer 0votes answeredFeb 7, 2021byhari_sh(26.4kpoints) The==outweighs in, so you're really trying word==True. >>> w = 'ab c' >>> ' ' in w == True 1: False >>> (' ' in w) == True 2: True However, you don't require==True by any means. in the event that...