// Function to check if a given string is a palindrome using recursion function isPalindrome(str) { // Base case: if the string has 0 or 1 characters, it's a palindrome if (str.length <= 1) { return true; } // Check if the first and last characters are equal if (str[0] !=...
# Enter stringword=input()# Check if string is palindrome using a loopis_palindrome=Truelength=len(word)foriinrange(length//2):ifword[i]!=word[length-i-1]:is_palindrome=Falsebreakifis_palindrome:print("Palindrome")else:print("Not Palindrome") ...
publicbooleanisPalindrome(String text){Stringclean=text.replaceAll("\\s+","").toLowerCase();intlength=clean.length();intforward=0;intbackward=length -1;while(backward > forward) {charforwardChar=clean.charAt(forward++);charbackwardChar=clean.charAt(backward--);if(forwardChar != backwardChar)r...
Here is source code of the Python Program to check whether a string is a palindrome or not using recursion. The program output is also shown below. defis_palindrome(s):iflen(s)<1:returnTrueelse:ifs[0]==s[-1]:returnis_palindrome(s[1:-1])else:returnFalsea=str(input("Enter string:...
False" if the string is not a palindrome}// Main functionintmain(){// Output the result of testing strings for being palindromescout<<"Is madam a Palindrome? "<<test_Palindrome("madam");cout<<"\nIs racecar a Palindrome? "<<test_Palindrome("racecar");cout<<"\nIs abc a Palindrome?
inti=2;while(i<=num/2){if(num%i==0){isPrime=false;break;}i++;} Top Related Articles: Sunny Number Program in Java Java Program to reverse the Array java program to check palindrome string using recursion System.out.println(“Enter a number for check in main method:”); ...
Step 4 ? Check the length of an array[ ] using length method in if-else condition. Step 5 ? If the length of the array[ ] is equal to zero then it will return an empty, otherwise if the length of an array is greater than zero then it will return an empty. Example Open Compiler...
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(String[] args) throws IOException { Scanner sc = new Scanner(System.in); System.out.println("Enter an URL"); String url = sc.next(); if(isUrlValid(url)) { URL obj = new URL(url); //Opening a connection HttpURLConnection conn = (HttpURLConnection) obj.openConnection(); //...
internalclassArmstrongNumberInCSharpUsingRecursion{staticvoidMain(){Console.Write("Enter a number: ");intnumber=int.Parse(Console.ReadLine());intdigits=number.ToString().Length;if(IsArmstrong(number,digits,0,number)){Console.WriteLine($"Yesss,{number}is an Armstrong Number!!");}else{Console.Wri...