Learn multiple methods to check if a string is null or empty in Java. Explore if-else statements, isEmpty() method, and Apache Commons StringUtils.
Sample Output: Input first string: Once in a blue moon Input second string: See eye to eye If the second string contains the first one? false Flowchart: For more Practice: Solve these Related Problems: Write a Java program to count the occurrences of a given substring within another string....
Learn how to effectively check if a Java string is null, empty, and whitespace. Enhance code reliability and prevent errors. Master string validation in Java now!
public static boolean isNumeric(String strNum) { if (strNum == null) { return false; } try { double d = Double.parseDouble(strNum); } catch (NumberFormatException nfe) { return false; } return true; } Let’s see this method in action: ...
1. String Starts with Specified Prefix or Value JavaString.startsWith()method checks if a string begins with the specified prefix substring. The argument prefix must be a standard substring and the regular expressions are not supported. ThestartsWith()method is an overloaded method and has two ...
The method removes all the white spaces present in a string. Example 2: Check if String with spaces is Empty or Null class Main { public static void main(String[] args) { // create a string with white spaces String str = " "; // check if str1 is null or empty System.out....
c) If aXbZc is true, aXbYZca is also valid, where a, b, c are either empty strings or a string consisting only of the letter X. Visual Presentation: Sample Solution: Java Code: // Importing necessary classesimportjava.util.PriorityQueue;importjava.util.Scanner;// Defining a class named ...
We can also usestring find() functionto check if string contains a substring or not. This function returns the first index position where substring is found, else returns -1. str1='I love Python Programming'str2='Python'str3='Java'index=str1.find(str2)ifindex!=-1:print(f'"{str1}"...
Check if a string is null or empty in XSLT 多条件查询 string.Format("/root/deviceList//item/guid[{0}]", strBuilder.ToString()) "/root/deviceList//item/guid[text()=\"h\" or text()=\"a\" or text()=\"c\"]"谓词嵌套var nodes = xmlDoc.SelectNodes(string.Format("/root/device...
public static boolean isnumeric(string strnum) { if (strnum == null) { return false; } try { double d = double.parsedouble(strnum); } catch (numberformatexception nfe) { return false; } return true; } let’s see this method in action: assertthat(isnumeric("22")).istrue(); ...