http://www.geeksforgeeks.org/function-to-check-if-a-singly-linked-list-is-palindrome/ 这里的reverse可以reverse整个list,这样空间需求就是O(n),不如这个网页写的O(1)的方法 1#include <iostream>2#include <vector>3#include <algorithm>4#i
("\nOriginal Singly List:\n"); displayList(head2); if (isPalindrome(head2)) printf("Linked list is a palindrome.\n"); else printf("Linked list is not a palindrome.\n"); // Example 3: Character palindrome linked list struct Node* head3 = newNode('M'); head3->next = newNode...
Problem: Implement a function to check if a singly linked list is a palindrome. 思路: 最简单的方法是 Reverse and compare. 另外一种非常经典的办法是用 Recursive 的思路,把一个list看成这种形式: 0 ( 1 ( 2 ( 3 ) 2 ) 1 ) 0 0 ( 1 ( 2 ( 3 3 ) 2 ) 1 ) 0 CC150里面给出的Code...
Learn how to check if a string is a palindrome in JavaScript while considering punctuation. This guide provides clear examples and explanations.
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