I am checking for url & return "valid" if url status code "200" & "invalid" if its on "404", urls are links which redirect to a certain page (url) & i need to check that page (url) status to determine if its valid or invalid on the basis of its status code. ...
It checks the phone number according to the country is valid or not. I use this:-- PhoneNumberUtil phoneUtil = PhoneNumberUtil.getInstance(); PhoneNumber numberProto = phoneUtil.parse("phone_number", ""); phoneUtil.isValidNumber(numberProto) == true ? "valid" : "phone ...
aPhone number you entered is not valid. Please check the number and enter a correct phone number 您输入的电话号码是无效的。 请检查数字并且进入一个正确电话号码[translate]
a好朋友一定要好好照顾自己。 The good friend wants certainly to look after well oneself.[translate] aPhone number you entered is not valid. Please check the number and enter a correct phone number. 您输入的电话号码是无效的。 请检查数字并且进入一个正确电话号码。[translate]...
Check if .NET string is valid in UTF8 Check if 1 year has passed Check if a string contains a letter Check if a user has FullControl on a folder Check if an array is in another bigger array using linq. check if an element that have Attribute with matching Value EXIST or NOT in X...
Returntrueif and only if the given stringSis valid. Example 1: Input:"aabcbc" Output:true Explanation: We start with the valid string "abc". Then we can insert another "abc" between "a" and "bc", resulting in "a" + "abc" + "bc" which is "aabcbc". ...
* Simple way to check if URL is valid or invalid? */ publicclassCrunchifySimpleValidateURL{ publicstaticvoidmain(String[]args){ UrlValidator crunchifyURLValidator =newUrlValidator(); Stringurl ="https://crunchify.com"; if(crunchifyURLValidator.isValid(url)){ ...
1. How to check if the iPhone is original using IMEI 2. Check the Model number and Serial number 3. Go through the physical appearance of the iPhone 4. Ensure the iPhone's internal parts are not changed 5. Network connectivity 6. Sync the new iPhone using Quick Start ...
aBut what we actually saw simply shocked us all 但什么我们实际上看见了简单地冲击了我们全部[translate] aThis is not a valid entry. Please check that the information is correct. 这不是一个合法的词条。 请检查信息是正确的。[translate]
classSolution {public:boolisValid(stringS) {while(!S.empty()) { auto pos= S.find("abc");if(pos !=string::npos) S.erase(pos,3);elsereturnfalse; }returntrue; } }; 方法2:使用栈的思想 遇到'c' 则检查栈内是否存在'a', 'b',并且要严格按照顺序排列 ...