In JavaScript, there is no built-in function to check if every character in a given string is in uppercase format or not. So, we have to implement our function. Here, we will create a function calledisUpperCase(), an anonymous arrow function, to tell us whether all the characters in a...
import re password= input("Enter in a password: ") if not re.search(r"[\d]+", password) and if not re.search(r"[A-Z]+", password): print('This password must contain at least 1 digit and at least 1 uppercase character') else: print('This password ...
ispunct() checks if a character is a punctuation character (a printable char, not a space, not alphanumeric) isspace() checks if a character is a whitespace character (see more later) isupper() checks if a character is uppercase isxdigit() checks if a character is an hexadecimal digit (...
check if the character // at index is in uppercase or not if ((str[index] >= 'A' && str[index] <= 'Z') || (str[index] == 32)) { check++; } else { check = 0; break; } } else { check = 0; break; } } if (check != 0) { cout << "String is in uppercase!"...
then print "Vowel". If it is a consonant, then it should print "Uppercase" if it is in uppercase and "Lowercase" If otherwise. If the character is numeric then it should check the value. If it is less than 5, then pri...
# Python program to check if a string is # palindrome or not # function to check palindrome string def isPalindrome(string): rev_string = string[::-1] return string == rev_string # Main code x = "Google" if isPalindrome(x): print(x,"is a palindrome string") else: print(x,"is...
(e.g. at least 8 characters, contains both uppercase and lowercase letters, and at least one number and one special character). Sample Solution: Python Code: importredefcheck_password_strength(password):score=0suggestions=[]# check lengthiflen(password)>=8:score+=1else:suggestions.append("Pas...
Step 2: We first assume the given string is a pangram. For this, initialize an integer flag to 1. Step 3: Iterate through each character in the String using Loop. Step 4: If the character is a letter (uppercase or lowercase), calculate its index in the alphabet and mark the correspo...
# Check if the current character 'i' is a vowel (lowercase or uppercase).result_str+=i# If it's a vowel, append it to 'result_str'.# Check if the length of 'result_str' is greater than or equal to 'n'.iflen(result_str)>=n:# If it is, return the first 'n' characters ...
); else if (lowercase_vowel || uppercase_vowel) printf("%c is a vowel.", c); else printf("%c is a consonant.", c); return 0; } Run Code Now, if the user enters a non-alphabetic character, you will see: Enter an alphabet: 3 Error! Non-alphabetic character....