functionpalindrome(str) {if(str.length===1) {returntrue; }varreplacedStr = str.toLowerCase().replace(/[^a-z0-9]/g,"");// 双指针 i 与 j,用来代表当前判断位置的索引for(vari =0, j = replacedStr.length-1; i < replacedStr.length/2; i++,j--) {// 如果检测到了不相同if(replace...
String.toLowerCase() 要求: palindrome("eye")应该返回一个布尔值 palindrome("eye")应该返回 true. palindrome("race car")应该返回 true. palindrome("not a palindrome")应该返回 false. palindrome("A man, a plan, a canal. Panama")应该返回 true. palindrome("never odd or even")应该返回 true. p...
如果给定的字符串是回文,返回true,反之,返回false。 如果一个字符串忽略标点符号、大小写和空格,正着读和反着读一模一样,那么这个字符串就是palindrome(回文)。 注意你需要去掉字符串多余的标点符号和空格,然后把字符串转化成小写来验证此字符串是否为回文。 函数参数的值可以为"racecar","RaceCar"和"race CAR"。
// Function to check if a given string is a palindrome using recursion function isPalindrome(str) { // Base case: if the string has 0 or 1 characters, it's a palindrome if (str.length <= 1) { return true; } // Check if the first and last characters are equal if (str[0] !=...
Step 1: We have to find out if the given string is a palindrome or not. So to do this task we will create a function called isPalindrome and in this function, we will pass a parameter of string as str. So for this str, we will check the palindrome condition. Step 2: After the...
import java.util.function.Predicate; public class Main { public static void main(String[] args) { // Define the palindrome check lambda expression Predicate < String > isPalindrome = str -> { String reversed = new StringBuilder(str).reverse().toString(); return str.equals(reversed); }; /...
using System;using System.Linq;namespace palindrome{class Program{publicstaticboolcheckPalindrome(string mainString){string firstHalf=mainString.Substring(0,mainString.Length/2);char[]arr=mainString.ToCharArray();Array.Reverse(arr);string temp=newstring(arr);string secondHalf=temp.Substring(0,temp.Len...
) else: print("The string is not a palindrome.") Run Code Output The string is a palindrome. Note: To test the program, change the value of my_str in the program. In this program, we have taken a string stored in my_str. Using the method casefold() we make it suitable for ...
# Python program to check if a string is # palindrome or not # function to check palindrome string def isPalindrome(string): result = True str_len = len(string) half_len= int(str_len/2) for i in range(0, half_len): # you need to check only half of the string if string[i] ...
publicbooleanisPalindromeReverseTheString(String text){StringBuilderreverse=newStringBuilder();Stringclean=text.replaceAll("\\s+","").toLowerCase();char[] plain = clean.toCharArray();for(inti=plain.length -1; i >=0; i--) { reverse.append(plain[i]); ...