com.rabbitmq.client.AlreadyClosedException: channel is already closed due to 异常通常表明 RabbitMQ 的通道(Channel)已经被关闭,而代码试图在通道关闭后继续使用它。 这个异常通常发生在以下几种情况: 通道被显式关闭: 代码中可能显式调用了 channel.close() 方法,或者连接(Connection)被关闭,导致所有相关通道也...
return new String(bytes, "UTF-8"); } catch (UnsupportedEncodingException $uniqueName) { throw useMagicTrickeryToHideThisFromTheCompiler($uniqueName); // This trickery involves a bytecode transformer run automatically during the final stages of compilation; // there is no runtime dependency on l...
发现问题后,第一时间查log,发现日志有很多业务代码的异常,AMQP的异常也有,信息如下: Caused by: com.rabbitmq.client.AlreadyClosedException: channel is already closed due to clean channel shutdown; protocol method: #method<channel.close>(reply-code=200, reply-text=Closed due to exception from Consumer...
if(isInClosed()){ thrownewIllegalStateException("Channel was already closed",inClosed); }elseif(isOutClosed()){ 代码示例来源:origin: jenkinsci/remoting @Override publicvoidrun(){ // if this EOF is unexpected, report an error. if(!t.getChannel().isInClosed()){ t.getChannel().terminate(...
There is already an open DataReader associated with this Connection which must be closed first 使用MVC4 EF Linq获取foreach列表循环的时候遇到了如下的问题:报错提示 There is already an open DataReader associated with this Connection which must be closed first 解决方法如下红色所示: @foreach (var it...
If this channel is already closed then invoking this method has no effect. This method may be invoked at any time. If some other thread has already invoked it, however, then another invocation will block until the first invocation is complete, after which it will return without effect. ...
}// send processes a send operation on an empty channel c.// The value ep sent by the sender is copied to the receiver sg.// The receiver is then woken up to go on its merry way.// Channel c must be empty and locked. send unlocks c with unlockf.// sg must already be dequeued...
2 deregister(voidPromise(), wasActive && !isActive()); 3 } 1. 2. 3. deregister实现:从eventLoop中注销channel deregister的调用栈: 1 io.netty.channel.AbstractChannel#deregister() 2 io.netty.channel.DefaultChannelPipeline#deregister()
其中显示问题原因在于channel已经被关闭导致,抛出异常。但是信息同时显示reply-code=200, reply-text=OK,这说明生产者一端的消息已经成功被消费者接收,初步判断异常与生产者一端无关。后来我检查了代码,发现了这么一个问题, 附上我的代码: Producer(这段代码是在《Rabbit MQ实战指南》的基础上修改的) ...
程序分析,代码运行到select的唯一case分支时,因为此时intChan为空,无法进行接收,所以阻塞,1s之后,通道关闭,二元接收值中的ok为false,所以执行答应The candidate case is closed. 再次看一个示例,到底哪个case被执行,或者default被执行 package main import "fmt" var channels = [3]chan int{ nil, make(chan int...