CF round1005(div2)总结 ps:本人被D题硬控1个半小时直接洪文,半夜掉大分,此博客是在极佳快死了的状态下写出来的,有一些类似人类的语言自行理解 [比赛链接](https://codeforces.com/contest/2064) 链接:A 首先,我们可以将所有连续的1合并为1个,因为这些1都可以在同一次操作中去除 然后,我们考虑,对于不在末尾...
CF Round 1005 题解合集 合集- 题解(39) 1.题解:P9923 [POI 2023/2024 R1] Przyciski01-242.题解:P6544 [CEOI2014] Cake01-243.题解:CF690A2 Collective Mindsets (medium)01-244.题解:AT_arc050_c [ARC050C] LCM 11101-245.题解:P11311 漫长的小纸带01-246.题解:CF815D Karen and Cards01...
Codeforces Round 1000 (Div. 2) 题目讲解 ABCDEF1 (CF2063) 01:13:27 Codeforces Round 1003 (Div. 4) 题目讲解 BCDEFGH (CF2065) 01:01:21 Codeforces Round 1005 (Div. 2) 题目讲解 ABCDE (CF2064) Educational Codeforces Round 174 (Div. 2) 题目讲解 ABCDE (CF2069) 46:11 Codeforces Rou...
#include<iostream>#include<cstdio>usingnamespacestd;constintN=1005;intn,m;inta[N],b[N];doublecalc(intk,doublew){if(k==1){printf("-1");exit(0);}returnw+w*1.0/(k-1);}intmain(){scanf("%d%d",&n,&m);for(inti=1;i<=n;i++)scanf("%d",&a[i]);for(inti=1;i<=n;i++...
IAEPC Preliminary Contest (Codeforces Round 999, Div. 1+2) 题目讲解 ABCDEF1 (CF2061) 01:07:34 Codeforces Round 1000 (Div. 2) 题目讲解 ABCDEF1 (CF2063) 01:13:27 Codeforces Round 1003 (Div. 4) 题目讲解 BCDEFGH (CF2065) 01:01:21 Codeforces Round 1005 (Div. 2) 题目讲解 ABCD...
this means that the player has lost in the round. So, if two or more players have the maximum number of points (say, it equals tom) at the end of the game, than wins the one of them who scored at leastmpoints first. Initially each player has 0 points. It's guaranteed that at ...
Codeforces Round #481 (Div. 3) 全题解 A题,题目链接:http://codeforces.com/contest/978/problem/A 解题心得:题意就是让你将这个数列去重,重复的数只保留最右边的那个,最后按顺序打印数列。set+map。 B题,题目链接http://codeforces.com/contest/978/problem/B 解题心得:让你将字符串中的包含xxx的子串...
this means that the player has lost in the round. So, if two or more players have the maximum number of points (say, it equals to m) at the end of the game, than wins the one of them who scored at least m points first. Initially each player has 0 points. It's...
Nowadays all circuses in Berland have a round arena with diameter 13 meters, but in the past things were different. In Ancient Berland arenas in circuses were shaped as a regular (equiangular) polygon, the size and the number of angles could vary from one circus to another. In each corner...
样品流动垫通过把样品从起始上样点转移到测试组件。在检测试纸条下游末端的吸水垫控制样品沿着膜片流动。 为了确保您的检测试纸条研发的开始不会太复杂,Whatman提供了完整的高质量样品流动垫材料。Whatman也研发了具有的流动性的吸水垫以保证很好的*性。 CF6 –结合物回流的解决方法 ...