The centre of the circle is given by the point ( a, b ) and the radius of the circle is r. Now, we will use the above equation to derive the general equation of the unit circle. The above equation is known as the central form of the equation of a circle. General Equation of a ...
Here, the centre of the given circle is at(4,-4). As the circle touches both the axes, its radius is 4 units. The equation of the circle is(x-h)²+(y-k)²=r²or,(x-4)²+{y-(-4)}²=4²or,(x-4)²+(y+4)²=16or,x²-8x+16+y²+8y+16=16or,x²...
View Solution Equation of circle of radius 5, centred on X -axis and passing through origin , is View Solution What is the equation of a circle whose center lies on the x-axis at a distance h from the origin and the circle passes through the origin ? View Solution ...
Find the centre and radius of the circle when given the equation. x^2 + y^2 = 9 Find the equation of the circle with radius 1 and center (5,-3). Find the equation of the circle with radius 3 and center (2, -5). Find an equation of a circle with ra...
The center of the circle is given as (2a,a−7). The diameter of the circle is given as 10√2, which means the radius r is half of the diameter:r=10√22=5√2 Step 2: Write the equation of the circleThe general equation of a circle with center (h,k) and radius r is given...
11 The equation of a circle with centre C is x2+ y2-8x+ 4y-5 = 0.(a) Find the radius of the circle and the coordinates of C.3]...…-nwng...--...-...-...-.--.--...-..---...-.-..-The point P (1, 2
Find the coordinates of the centre of the circle b) Show that the radius of the circle is kv13 where k is an exact fraction to be found c)Find an equation of the tangent to the circle at the point (4, 8), giving your answer in the form ax + by + c =0, where a, b ...
14. A circle has centr e^candequationx^2+y^2-6x+14y+49=0(a)Find the centre of the circle.(...)(2)(b)Find the radius of the circle(2) 相关知识点: 试题来源: 解析 (a)(x-3y)^2-9^2+14y+4y=0.99-0.92-0.96+3.29)=99(3,7)(b)3 反馈 收藏...
Red Write down an equation of the circle with the given centre and radius in each case(1)centre(1, 3)radius 3 (2)centre(4, -6) radius 5 (3)centre(-1, -8) radius v3 相关知识点: 试题来源: 解析 (1)(x-1)^2+(y-3)^2=9(2)(x-4)^2+(y+6)^2=25(3)(x+1)^2+(y...
1. Find the equation of the circle with(i) Centre at origin and radius 4.(ii) Centre at (-3, -2) and radius 6.(iii) Centre at (2, -3) and radius 5.(iv) Centre at (-3, -3) passing through point(-3,-6) 相关知识点: 试题来源: 解析 (i)x^2+y^2=16(ii)x^2+y^...