The GeekDads Episode #102: Causation Does Not Imply Causality (GeekDad Weekly Rewind)GeekDad Rewind
Yet, association does not automatically imply causation15. Association may arise from shared causes, statistical coincidences, or the influence of confounding factors. An example of association can be observed in the increased rates of chronic respiratory diseases in regions undergoing significant ...
Yet, association does not automatically imply causation15. Association may arise from shared causes, statistical coincidences, or the influence of confounding factors. An example of association can be observed in the increased rates of chronic respiratory diseases in regions undergoing significant ...
This approach to causality assumes that causes “operate at equal speed and in the same way across all cases. (…) Explanations should emphasize immediate causation. (…) It is not necessary to know the particular twists and turns of an entity's history to explain it” (Van de Ven, 2007...
Although Ragin does not discuss realist metatheory, his approach has much in common with realism's understanding of the nature of causation. Coming from a different direction, Karl Popper's attention in his later work to “single case probabilities” has similar implications for our understanding ...
It just does things with it. If it had other things maybe it would try to do things with them too, but there does not appear to be anything else. Originally posted by Mentat It has an "internal rule" that is utterly unprovable (=assumption). Why unprovable ? It would seem ...
The pre-decay causal past is simply cut off: it does not exist, at least in its "proactive" role. There is nothing capable of instantiating actions that constrain atoms in any way. It, therefore, makes more sense to speak of the absence of causes rather than of their identity. Thus QM...
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the estimated coefficients of Eqs. (A4) and (A10) demonstrate that the elasticity of population is greater than the elasticity of income (\({\upbeta }_{2}>{\beta }_{1}\)). This result implies that the mechanism of risk sharing exists in the two equations but does not exist in other...
If ϕ does not fail on any finite prefix of π, we take k = ∞ (then π[0..∞] naturally stands for π, and we have π |= ϕ). We can now define the following. Explaining Counterexamples Using Causality 99 Definition 3 (Criticality in counterexample traces). A pair s, v is ...