you can pass the int value as void pointer like (void *)&n where n is integer, and in the function accept void pointer as parameter like void foo(void *n);and finally inside the function convert void pointer to int like, int num = *(int *)n;. this way you won't get any warni...
将int变量转为(void*)时出现错误 error: cast to pointer from integer of different size [-Werror=int-to-pointer-cast] 这是由于int类型为32位,指针为long long 64位 解决方法:(void*)(intptr_t)
pointer.c:7:13: warning: dereferencing 'void *' pointer printf("%d",*p); ^~ pointer.c:7:13: error: invalid use of void expression printf("%d",*p); Some users say that the error appears only when we try to use the result of the derefenciation and tha...
char **argv) { int foo = 0; void *bar = foo; (void) (void *) foo; return 0; } % clang-14 --version | grep version clang version 14.0.6 % clang-14 test.c -o test test.c:7:8: warning: incompatible integer to pointer conversion initializing 'void *' with an expression...
使用static_cast：它是精确描述这里所进行的转换的最窄的类型转换。
5.3.2 Struct Pointer Cast of Void Pointer In the following example, the void pointer vp, is cast as a struct pointer. With lint -Xalias_level=weak (or higher), this example generates a warning. struct foo { int a; int b; }; struct foo *f; void *vp; void main() { f = (stru...
doi:10.1007/978-1-4842-6643-4_42When printing out a pointer's value (the memory address it points to) using a printf function and a %p format specifier, we need to cast that pointer to type void*first. Simply trying to print out...Slobodan Dmitrovi...
例如将一个非 const 的对象转换为 const 对象,或将int 转换为double等等。它也可以用来执行上述多种转换的反向转换,例如将void*指针转为typed指针,将pointer-to-base转为pointer-to-derived。但是他无法将const转为non-const,这个只有const-cast才能够办到。
Question:How do you cast a function pointer to a void*? (You’re trustworthy and wouldn’t dare to do anything evil with it, right?) Answer:Maybe your first thought was, wellreinterpret_cast<void*>(&f)of course. That was mine, at least. Well, it turns out, C++ wants to support ...
void f(int v) const { // this->i = v; // compile error: this is a pointer to const const_cast<type *>(this)->i = v; // OK as long as the type object isn't const } }; int main(){ [[maybe_unused]] void (type::*pmf)(int) const = &type::f; // pointer to membe...