百度试题 结果1 题目Find the Cartesian equation of the locus given by x=sin θ, y=2\ sin θ cos θ . 相关知识点: 试题来源: 解析 y^2=4x^2(1-x^2) 反馈 收藏
相关知识点: 试题来源: 解析 【解析】1+y/(x-1)⋅(y+1)/x=0 0 or x(x-1)+y(y+1)=0or (x-1/2)^2+(y+1/2)^2=1/2Locus(1/2,-1/2)This is the equation of the circle centre (, -) radius √ 反馈 收藏
【题目】Find the cartesian equation of the following loci.Define the loci ingeometric terms.Illustrate each on an Argand diagram.)arg (z-1)-arg (z+i)=T2 相关知识点: 试题来源: 解析 【解析】-|||-1+y_.y+1-|||-=0orx(x-1)+y(y+1)=0-|||-x-1x-|||-or(x-)2+(y+)2=.-...
The Navier-Stokes equations can be transformed in a similar manner, although the transformation of the viscous terms is somewhat more complicated and will not be given here. Since the potential equation is simply the continuity equation (the first of the conservation laws comprising the Euler equati...
This quadratic form can be interpreted as an equation of an ellipsoid, called a confidence region in statistics or an error ellipsoid in geodetic practice. The understanding is that if we know the covariance matrix C and select a probability level α we are comfortable with, then the vector ...
Wikipedia Related to cartesian plane:Cartesian plain [kär′tēzh·ən ′plān] (mathematics) A plane whose points are specified by cartesian coordinates. McGraw-Hill Dictionary of Scientific & Technical Terms, 6E, Copyright © 2003 by The McGraw-Hill Companies, Inc. ...
Cartesian equation:. Cartesian parametrization in theellipticcase: where, e=c/a. Curvilinear abscissa:. Cartesian parametrization in thehyperboliccase:. The notion of Sturmrouletterefers to the locus of the centre of a centred conic rolling without slipping on a line; it is said to beellipticof...
The characteristic equation of the control system 42 is defined by setting the denominator of equation (16) equal to zero and is given by: 1+(1RtC τ)1s(s+1τ)=0(18) The zeros and poles of the characteristic equation can be determined by the expression: KZ...
where M is the 3 × 3 rotation matrix, KC is the camera calibration matrix and t is the translation vector which is actually the zero vector because the origin of the camera frame is the focal point. The directional vector ct in Figure 3 can be obtained by the following equation: (12)...
An equation representing a locus L in the n-dimensional Euclidean space. It has the form L:f(x_1,...,x_n)=0, (1) where the left-hand side is some expression of the Cartesian coordinates x_1, ..., x_n. The n-tuples of numbers (x_1...,x_n) fulfilling t