12年级向量与微积分 Cartesian Equation 12年级向量与微积分 Cartesian Equation of a plane #加拿大高中留学 #美国高中留学 #微积分 - 北美高中数学陈老师于20240315发布在抖音,已经收获了372个喜欢,来抖音,记录美好生活!
a point Q and a Cartesian equation for a plane V are given. Compute the distance of Q to V as follows: First find the line through Q that is perpendicular to V; next, find the point R of intersection of this line and V; finally, calculate the distance from Q to R to obtain the...
The Cartesian or scalar equation of a plane in ℝ3 has the form: A⋅x +B⋅y + C⋅z + D = 0, where A, B, C, D are real-valued parameters. The vector A,B,C is normal (perpendicular) to the plane.Change the coefficients of the ...
百度试题 结果1 题目 Find a Cartesian equation for the plane with the given normal vector n and passing through the given point P.n=(9,-3,7), P=(6,0,-9) 相关知识点: 试题来源: 解析 9x-3y+7z+9=0 反馈 收藏
百度试题 结果1 题目【题目】【题目】Find the cartesian equation of the plane which passes through the point (3,-4,1 )and which is【题目】 相关知识点: 试题来源: 解析 【解析】 【解析】 反馈 收藏
Find the cartesian equation of the plane which passes through the point (1,2,3) and contains the line of intersection of the planes 2x-y+z=4 and x+y+z=4. 相关知识点: 试题来源: 解析 5x-y+3z=12 结果一 题目 下列各句中,没有语病的一项是( ) A. 我们从文章风格的发展看,他是比...
Find the vector and Cartesian forms of the equationi of the plane containing the two lines. →r=(ˆi+2ˆj−4ˆk)+λ(2ˆi+3ˆj+6ˆk) and →r=(9ˆi+5ˆj−ˆk)+μ(−2ˆi+3ˆj+8ˆk). View Solution Find the vector and catesian equations of the pla...
Cartesian equation Cartesian plane See More Nearby Entries Cite this Entry Style “Cartesian equation.” Merriam-Webster.com Dictionary, Merriam-Webster, https://www.merriam-webster.com/dictionary/Cartesian%20equation. Accessed 1 Jan. 2025. Copy Citation Share...
结果1 题目 Find the cartesian equation of the plane which passes through the point (3,-4,1) and which is parallel to the plane containing the point (1,2,-1) and the line r=t(pmatrix) 1 1 1(pmatrix) . 相关知识点: 试题来源: 解析 3x-2y-z=16 反馈 收藏 ...
百度试题 结果1 题目Find a Cartesian equation of the plane which passes through the point (1,1,1) and contains the line with equation (x-2)3= (y+4)1= (z-1)2.相关知识点: 试题来源: 解析 -10x-2y+16z=4 反馈 收藏