而 cannot recognize input near 'failed' ':' 'se' 则指出了无法识别的输入片段。 2. 分析错误原因 输入格式错误:输入的内容可能不符合解析器预期的格式。在这个例子中,failed: se 很可能不是一个有效的输入格式。 特殊字符或符号:如果输入中包含了特殊的字符或符号,而解析器没有处理这些字符的逻辑,也会导致...
FAILED: ParseException line 1:17 cannot recognize input near 'student2' 'select' 'id' in destination specification 1 2 3 4 5 6 7 错误: insertoverwrite student2selectid,namefromstudent; 正确: insertoverwritetablestudent2selectid,namefromstudent; 1 2 语法: INSERT(INTO| OVERWRITE)TABLEtablename ...
关于FAILED: ParseException line 4:0 cannot recognize input near ')' 'row' 'format' in column name or constraint问题的解决 问题描述 在我使用建表语句在hive数据库里面建表时,就出现了这个错误: 问题解决 指示的是第四行数据没有被访问到; 那就是上面的语句有问题: 观察发现,我定义的count字符串后面多...
出现这个报错的原因多半出现了子查询形式的情况,比如 select*from(select*fromtablewherename='zhangsan') 重点在于自查询要给一个临时命名,不然就会出现 cannot recognize input near in joinSource 解决:给个临时表名就好了 select*from(select*fromtablewherename='zhangsan')tmp 注:名字随意,不一定叫tmp...
insert overwrite table employees partition(country, state) select ...,se.cnty, se.st from staged_employees se; 5、cannot recognize input near 报错 报错:Error: Error while compiling statement: FAILED: ParseException line 10:8 cannot recognize input near'(' 'select' 'statis_id' in joinSource(...
Oracle Data Integrator - Version 12.2.1.3.0 to 12.2.1.4.220702 [Release 12c]: ODI Error "cannot recognize input near '('" Loading Data from Hive to Hive with Multipl
ParseException line 1:162 cannot recognize input near '' '' '' in statement Labels: Apache Hive colorsoflife Rising Star Created 12-18-2015 06:30 PM I am getting error when running the below query ; Error occurred executing hive query: Error while compiling statement: FAILED...
Error "cannot recognize input near '(' 'select' 'sum' in subquery source." with Hive ODBC Driver Steps to Reproduce Clarifying Information Reproducible Steps: 1.Create a DSN for Apache Hive Wire Protocol Driver. 2.Execute the following SELECT query using the ‘example’ sample. ...
hive不支持 "INTO"，使用 "CREATE TABLE AS"。
写了一个简单的shell脚本调用hive执行组装的sql,在执行时总是报cannot recognize input near '<EOF>' in select clause错误, 单独在hive提示符下却能正常执行。 #!/bin/bashkeyname="type"sql=" select tags['$keyname'] from user_tags "echo${sql}hive -e${sql} ...