类型错误，多是你把一个二维数组名传给一个指向某种数据类型的指针 要传递也是传递给指向指针的指针
int add(int x,int y){ return (x+y);} double add(int x,double y){ return (x+y);} double add(double x,double y){ return (x+y);} double add(int x,double y,double z){ return (x+y+z);} char* add(char x,char y){ static char buff[3] = {x}; // 合并字...
aich liebe dich,i love you 我爱你,我爱你[translate] acannot convert from 'char (*)[30]' to 'char *' 不能从‘炭灰转换(*) (30)’成‘炭灰*’[translate]
Return to Answer There is a type calledchar [], but it's anincomplete array typewhich is a somewhat advanced topic. If it were compiling in strict mode, the compiler would have reported that an incomplete array cannot be a class member, and that should prevent the error you got. But ac...
char name[15]; int age; int main() { srand(time(0)); char* Plocation = &location[rand()%5]; //[Error] cannot convert 'char (*)[20]' to 'char*' in initialization char* Pcolor = &color[rand()%5]; //[Error] cannot convert 'char (*)[7]' to 'char*' in initialization ...
char age[10];}STU;int main(){ STU stu={"1001","12","45","19"}; STU stu1,stu2; int x; char ch1[10]; //原代码char *ch=ch1; //原代码FILE *f=fopen("D:\letter.txt","w+"); FILE *f=fopen("D:\\letter.txt","w+");...
error: cannot convert ‘const char (*)[5]’ to ‘char*’ in initialization 原因 如果只给出一个字符串,那么会默认为它的类型是 const char *,是一个常量类型。 而指针无法指向一个常量的地址,所以不能这样写。 解决方法 ①定义一个字符数组,让p指向它的首地址: ...
char[strlen[cp.brand]+1];//两处strlen后面是普通括号而不是中括号.computer& computer::operator =(const computer &cp) // ::符号及前面的类名去掉.之后一切OK.
【题目】error C2440:'=':cannot convert fro m'char*1 to 'char'#include using namespace std; int min(int a, int b); float min(float a,float b); char* min (char* a, char*b); void main() { int min(int a, int b); float min(floa t a, float b); char* min (char* a...
[微笑]您好，亲，非常开心回答您你的问题，程序运行中+cannot+convert+from+char+to+int，帮您查询到 ，char[strlen[cp.brand]+1];//两处strlen后面是普通括号而不是中括号.computer& computer::operator =(const computer &cp) // ::符号及前面的类名去掉.之后一切OK.